菜鸟不知道的printf()小窍门

float n1 = 3.0;
double n2 = 3.0;
 
 
long n3 = 2000000000;
long n4 = 1234567890;
 
long n5 = 250;
long n6 = 213;
 
 
 
printf("%ld %ld %ld %ld %ld %ld/n",n1,n2,n3,n4,n5,n6);
 
n5和n6对应输出是什么？别试代码，直接看哦～！
摘自 huqinweI987的专栏