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    <title>C++</title>
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    <description>Latest 500 infos of C++</description>
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      <title>岁月联盟-中国信息安全门户网站（老牌黑客网站）</title>
      <link>https://www.syue.com/</link>
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    <item>
      <title><![CDATA[二叉排序树]]></title>
      <description><![CDATA[ 		cpp 
#include&amp;lt;iostream&amp;gt; 
using namespace std; 
 
struct BiTree 
{ 
    int data; 
    BiT ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24708.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24708.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 17 Nov 2012 03:25:07 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ Nandflash 驱动移植]]></title>
      <description><![CDATA[ 		在飞凌提供的BSP中，Nandflash采用的是FMD+PDD的结构，PDD主要是应对上层的接口，这里我们不需要修改，直 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24707.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24707.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 17 Nov 2012 02:26:42 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[CF 6E Exposition(RMQ | 线段树，二分)]]></title>
      <description><![CDATA[ 		
题目大意：
给n个数，然后找出最长的一段子序列（不需要连续），使得这段子序列中的最大值与最小值之差 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24706.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24706.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 17 Nov 2012 02:12:11 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[一个简单的在本地传输文件的网络程序]]></title>
      <description><![CDATA[ 		经常在CSDN贴吧看见很多关于网络之间传输的例子（比如传输截屏文件），所以很想写一个作为学习。此程序设 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24705.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24705.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 17 Nov 2012 01:49:59 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu1316 斐波纳契 大数 二分]]></title>
      <description><![CDATA[ 		hdu1316cpp 
#include&amp;lt;iostream&amp;gt; 
#include&amp;lt;cstring&amp;gt; 
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt;algorithm&amp;gt; 
u ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24704.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24704.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 17 Nov 2012 01:47:24 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu1358 KMP-next数组的应用]]></title>
      <description><![CDATA[ 		hdu1358next数组贮存的是String中前i位字符 最长相同的前后缀长度+1。
i-nexti 则表示前i 位中循环节的 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24703.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24703.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 17 Nov 2012 01:25:14 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[在顺序存储模式下将所有的负数放到正数前面的三种算法]]></title>
      <description><![CDATA[ 		test1的时间复杂度最高，test2的时间复杂度优于test1，test3的时间复杂度最小，所用的时间最少
cpp 
 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24702.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24702.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 17 Nov 2012 00:54:46 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[error C2248]]></title>
      <description><![CDATA[ 		C++错误
1、错误描述  
cpp 
error C2248: &amp;amp;ldquo;std::basic_ios&amp;lt;_Elem,_Traits&amp;gt;::basic_ios&amp;amp;rdquo ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24701.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24701.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 17 Nov 2012 00:25:23 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Google C++ 编程规范 1.3]]></title>
      <description><![CDATA[ 		Inline Functions内联函数▽Define functions inline only when they are small, say, 10 lines or less. ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24700.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24700.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 16 Nov 2012 06:04:08 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Codeforces_9D-How many trees?]]></title>
      <description><![CDATA[ 		cpp
/**题目大意：给定1~n各节点，建立二叉搜索树，求树的深度大于等于h的个数
 *本题纠结一天未果， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24699.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24699.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 16 Nov 2012 05:28:13 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[初学C++正则表达式（regex）]]></title>
      <description><![CDATA[ 		由效果产生学习的兴趣，即使失败，但至少不会中途作废。正则表达式，语法看起来很多啊！ 本文做一个简单的 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24698.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24698.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 16 Nov 2012 02:13:03 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 1226(最长公共子串含逆序）]]></title>
      <description><![CDATA[ 		Substrings
Time Limit: 1000MS   Memory Limit: 10000K
Total Submissions: 9639   Accepted: 3319
D ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24697.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24697.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 16 Nov 2012 00:55:03 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[如何编译libfreetype]]></title>
      <description><![CDATA[ 		libfreetype是为跨平台设计的。在windows下要编译的话，可以直接打开freetype-2.4.10/builds/win32/vc200 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24696.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24696.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 16 Nov 2012 00:46:57 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj 2528 Mayor&#039;s posters(线段树,离散化,成段更新染色)]]></title>
      <description><![CDATA[ 		
题目大意：
在长度为10000000的墙上贴海报，海报的高度和墙的高度一样，不同的海报覆盖在不同的区域。 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24695.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24695.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 16 Nov 2012 00:38:25 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[zoj 1610 Count the Colors(线段树，成段更新染色)]]></title>
      <description><![CDATA[ 		
题目大意：
在一条长度为8000的线段上染色，每次把区间a,b染成c颜色。显然，后面染上去的颜色会覆盖 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24694.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24694.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 15 Nov 2012 08:53:21 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 1207 The 3n + 1 problem]]></title>
      <description><![CDATA[ 		一、题目信息
The 3n + 1 problem
Time Limit: 1000MS   Memory Limit: 10000K
Total Submissions: 44 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24693.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24693.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 15 Nov 2012 08:38:14 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ 类 - 3C++ Primer 学习笔记]]></title>
      <description><![CDATA[ 		cpp
class Sale_item 
{ 
public: 
    // 隐式使用string 的默认构造函数初始化 isbn 
    Sale_ ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24692.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24692.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 15 Nov 2012 08:30:23 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++自带的古老的诅咒]]></title>
      <description><![CDATA[ 		
话说，在大学刚接触C语言时，我们的老师便不断地！不断地！！不断地！！！告诉我们要把main函数分为5个 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24691.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24691.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 15 Nov 2012 06:20:44 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[算法——字节高低位交换]]></title>
      <description><![CDATA[ 		问题
对一个字节数据，逐个交换其高低位，例如11010001，经过0-7，1-6，2-5，3-4对应位的交换，变成1000 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24690.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24690.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 15 Nov 2012 06:16:32 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[uva_10404-Bachet&#039;s Game]]></title>
      <description><![CDATA[ 		cpp 
/**博弈题。。这种题目的特点就是&amp;amp;mdash;&amp;amp;mdash;想到方法后很简单，想不到
 *就做不出了。。开始 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24689.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24689.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 15 Nov 2012 06:10:28 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[uva_112-Tree Summing]]></title>
      <description><![CDATA[ 		cpp 
/**这道题的难度在于建树，因为输入可能不在一行，所以不能用字符串接收
 *必须一个一个读，我这 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24688.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24688.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 15 Nov 2012 05:50:35 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 3461(模式匹配数&amp;amp;amp;覆盖函数）]]></title>
      <description><![CDATA[ 		Oulipo
Time Limit: 1000MS   Memory Limit: 65536K
Total Submissions: 14051   Accepted: 5667
Desc ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24687.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24687.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 15 Nov 2012 05:41:40 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[c++中多继承同名隐藏的两种继承方式]]></title>
      <description><![CDATA[ 		cpp 
虚基类的作用是为了避免派生类从基类中继承过来的同名成员同时产生多个副本。 
图解：
祖父类- ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24686.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24686.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 15 Nov 2012 05:23:11 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[jQuery mobile，解决form表单提交的乱码问题]]></title>
      <description><![CDATA[ 		在&amp;lt;meta charset=&amp;quot;gb2312&amp;quot; /&amp;gt;的页面使用form表单提交数据会出现乱码的问题,都将数据转为了UTF-8了.解决方 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24685.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24685.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 15 Nov 2012 02:14:43 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 3468(成段更新）]]></title>
      <description><![CDATA[ 		线段树的成段更新
Time Limit: 5000MS   Memory Limit: 131072K
Total Submissions: 38010   Accepted: ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24684.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24684.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 15 Nov 2012 01:11:15 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[掷骰子游戏]]></title>
      <description><![CDATA[ 		编写程序模拟掷骰子游戏。已知掷骰子游戏的游戏规则为：每个骰子有6面，这些面包含1、2、3、4、5、6六个点 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24683.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24683.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 14 Nov 2012 09:09:34 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[c++ 理解 volatile ,mutable , const 及 const mutable]]></title>
      <description><![CDATA[ 		mutalbe的中文意思是&amp;amp;ldquo;可变的，易变的&amp;amp;rdquo;，跟constant（既C++中的const）是反义词。
在C++中， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24682.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24682.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 14 Nov 2012 09:07:26 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[算法设计矩阵乘法]]></title>
      <description><![CDATA[ 		题目
设A1,A2,&amp;amp;hellip;,An为矩阵序列，Ai为Pi-1&amp;amp;times;Pi阶矩阵，i = 1,2,&amp;amp;hellip;,n. 确定乘法顺序使得 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24681.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24681.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 14 Nov 2012 08:50:20 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++ static ，extern以及全局变量之间的相关逻辑]]></title>
      <description><![CDATA[ 		全局变量，就是指那些定义在函数之外的变量，当然也是定义与类之外的变量。
（1）全局变量会被自动初始化 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24680.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24680.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 14 Nov 2012 08:10:37 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++完美实现Singleton模式]]></title>
      <description><![CDATA[ 		Singleton模式是常用的设计模式之一，但是要实现一个真正实用的设计模式却也不是件容易的事情。
标准的实 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24679.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24679.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 14 Nov 2012 07:35:48 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++中CONST迭代器 和 CONST_ITERATOR的区别]]></title>
      <description><![CDATA[ 		话说这两个区别非常大，但是不太好理解啊，而且感觉解释也是各种绕口。说一下我自己的理解吧。
    cons ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24678.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24678.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 14 Nov 2012 07:29:49 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[二叉树的三种遍历(递归算法)]]></title>
      <description><![CDATA[ 		1 struct Node
 2 {
 3     int data;
 4     Node* lchild;
 5     Node* rchild;
 6 }
 7 void p ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24677.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24677.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 14 Nov 2012 07:06:37 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++将字符串转换成数字]]></title>
      <description><![CDATA[ 		 1 int changestr(char* str)
 2 {
 3        int len = strlen(str);
 4        int sum = 0;
 5    ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24676.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24676.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 14 Nov 2012 06:55:36 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++模板会使代码膨胀吗]]></title>
      <description><![CDATA[ 		今天和同事说到C++模板会使代码膨胀, 可同事觉得不会。
同事的依据是: 如果模板会使代码膨胀, 那么ATL和 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24675.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24675.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 14 Nov 2012 06:37:36 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++中经典的单向链表反转]]></title>
      <description><![CDATA[ 		 1 struct linka {
 2 int data;
 3 linka* next;
 4 };
 5 void reverse(linka*&amp;amp; head) {
 6 if(he ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24674.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24674.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 14 Nov 2012 06:33:31 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++使用Uniscribe进行文字自动换行的计算和渲染]]></title>
      <description><![CDATA[ 		在使用Uniscribe之前，我们先看看利用Uniscribe我们可以做到什么样的效果：  通过Uniscribe，我们可以获得 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24673.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24673.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 14 Nov 2012 06:07:08 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[zoj-1015-fishing net 弦图的判断]]></title>
      <description><![CDATA[ 		算法：先对图进行重新编号，然后根据新的编号检查
cpp
#include &amp;lt;cstdio&amp;gt;  
#include &amp;lt;cstring&amp;gt;  
 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24672.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24672.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 14 Nov 2012 05:28:31 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[UVA 11991]]></title>
      <description><![CDATA[ 		cpp 
#include &amp;lt;iostream&amp;gt; 
#include &amp;lt;vector&amp;gt; 
#include &amp;lt;map&amp;gt; 
#include &amp;lt;cstdio&amp;gt; 
using names ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24671.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24671.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 14 Nov 2012 00:46:59 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[关于c++中类的继承与派生]]></title>
      <description><![CDATA[ 		c++class
cpp 
#include&amp;lt;iostream&amp;gt; 
using namespace std; 
class A{ 
public:   
      int x;  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24670.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24670.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 13 Nov 2012 08:12:31 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[private继承与复合]]></title>
      <description><![CDATA[ 		private继承定义：private继承而来的所有成员，在derived中都会变成private属性。
应用场合：当一个意欲 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24669.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24669.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 13 Nov 2012 06:55:42 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj 3067 Japan(线段树 | 树状数组)]]></title>
      <description><![CDATA[ 		
题目大意：
在Japan的东西两边都有海岸线，且都是南北方向的。两边分别有n，m个城市，他们的编号分别都 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24668.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24668.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 13 Nov 2012 06:11:56 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu_1054-Strategic Game]]></title>
      <description><![CDATA[ 		cpp 
/**树形DP，推出状态转移方程：
 *不选择当前节点：
 *  dpi0 += dpNodei.sonj1; ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24667.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24667.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 13 Nov 2012 06:10:54 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[216 - Getting in Line]]></title>
      <description><![CDATA[ 		cpp 
描述：水题，就不解释了&amp;amp;hellip;&amp;amp;hellip; 
 
#include &amp;lt;iostream&amp;gt; 
#include &amp;lt;cstdio&amp;gt; 
#inc ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24666.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24666.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 13 Nov 2012 05:29:58 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj2728-最小比率生成树/0-1分数规划/二分/迭代]]></title>
      <description><![CDATA[ 		题目意思：
有n个村庄，村庄在不同坐标和海拔，现在要对所有村庄供水，只要两个村庄之间有一条路即可，建 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24665.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24665.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 13 Nov 2012 05:26:40 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Effective C++ 资源管理小结]]></title>
      <description><![CDATA[ 		
我发现，第一遍读书总是不能清楚的认识到问题的本质，我们还需要回过头去总结，因此，我决定以后每读一 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24664.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24664.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 13 Nov 2012 03:36:38 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[当C++遇到IOS应用开发---Dict集合]]></title>
      <description><![CDATA[ 		
     在Object-c中，字典（KEY/VALUE）使用NSDictionary 和NSMutableDictionary(可变长)。使用语法如下 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24663.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24663.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 13 Nov 2012 03:08:38 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 3065]]></title>
      <description><![CDATA[ 		
AC自动机。。建好字典树，找到fail指针。然后查询。存模版题，需要注意当查到不是大写字母的时候要 改变 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24662.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24662.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 13 Nov 2012 02:21:34 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[CF #137 DIV2]]></title>
      <description><![CDATA[ 		A题。
给你一个序列，给你两个操作。第一个操作是将第K个数加到序列最后，第二个操作是将第一个数删除。 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24661.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24661.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 13 Nov 2012 01:57:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[高质量C/C++编程指南--表达式和基本语句]]></title>
      <description><![CDATA[ 		此系列文章实为对《高质量程序设计指南--C++/C语言》的重点摘要总结
本篇总结的为表达式和基本语句：运算 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24660.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24660.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 13 Nov 2012 01:31:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[算法导论-红黑树C++实现]]></title>
      <description><![CDATA[ 		红黑树的定义：一棵二叉查找树如果满足下面的红黑性质，则为一棵红黑树：1）每个节点或是红的，或是黑的。 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/24659.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/24659.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 13 Nov 2012 01:14:43 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[动态规划-装配线调度]]></title>
      <description><![CDATA[ 		问题描述：一个找出通过工厂装配线的最快方式的制造问题。共有两条装配线，每一条装配线上有n个装配站，编 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22763.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22763.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 13 Nov 2012 01:11:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++读写汉字，C++处理中文字符]]></title>
      <description><![CDATA[ 		C++对多语言文本字符的支持，通过宽字符来解决。只要将输入输出设备绑定到一个本地的locale对象上即可。l ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22762.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22762.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 13 Nov 2012 00:45:19 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[模拟发扑克牌程序]]></title>
      <description><![CDATA[ 		cpp
#include&amp;lt;stdio.h&amp;gt; 
#include &amp;lt;string.h&amp;gt; 
#include &amp;lt;stdlib.h&amp;gt; 
#include &amp;lt;time.h&amp;gt; 
 
 
s ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22761.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22761.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 10 Nov 2012 03:45:43 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Cstring使用问题和struct结构体初始化方法汇总]]></title>
      <description><![CDATA[ 		今天在写程序为cstringarray变量操作时遇见：
ASSERT_VALID fails with illegal vtable pointer.
Asser ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22760.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22760.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 10 Nov 2012 03:07:21 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[高质量C/C++编程指南--程序版式]]></title>
      <description><![CDATA[ 		良好的代码版式有助于阅读代码和进行维护。可以设想，没有良好的排版的文章，估计读者看不到一半就没耐心 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22759.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22759.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 10 Nov 2012 02:22:33 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++ STL学习之八逆向迭代器reverse_iterator]]></title>
      <description><![CDATA[ 		对于逆向迭代器，很重要的一点是需要弄清楚逻辑位置和实际位置二者的区别。下图显示了逆向迭代器的位置和 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22758.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22758.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 10 Nov 2012 01:07:52 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[数据结构 二叉树 索引链表 及其索引话 输出]]></title>
      <description><![CDATA[ 		cpp 
#include &amp;lt;iostream&amp;gt; 
#include &amp;lt;string.h&amp;gt; 
using namespace std; 
class tree 
{ 
public ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22757.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22757.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 10 Nov 2012 00:47:59 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj2516-经典最小费用最大流-有点难度]]></title>
      <description><![CDATA[ 		题目意思，这个理解起来就很费劲
       有N个供给商，M个雇主，K种物品。每个供给商对每种物品的的供给 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22756.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22756.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 09 Nov 2012 09:05:13 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[在宏定义中使用可变参数]]></title>
      <description><![CDATA[ 		    实际项目中，我们为了方便，经常会使用宏定义函数， 这样方便调用且简洁直观。    这里介绍可变参数在 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22755.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22755.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 09 Nov 2012 08:53:55 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ie6 IE7 IE8 多浏览器css写法]]></title>
      <description><![CDATA[ 		ie6 IE7 IE8 多浏览器css 写法 在网站设计的时候，应该注意css样式兼容不同浏览器问题，特别是对完全使用 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22754.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22754.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 09 Nov 2012 05:15:55 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[关于C++中的赋值与拷贝]]></title>
      <description><![CDATA[ 		　　很久没有用Ｃ++了，今天看到一道关于赋值与拷贝的面试题，准备写几句代码验证下。　　首先，讲下验证 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22753.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22753.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 09 Nov 2012 03:56:39 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[编程命名规则]]></title>
      <description><![CDATA[ 		一个好的项目，通过命名是否规范，第一眼就可以看出项目质量的30%，所以摘录了些如下：
编程命名中的7+1 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22752.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22752.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 09 Nov 2012 02:32:28 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 2795 Billboard(线段树)]]></title>
      <description><![CDATA[ 		
题目大意：
给一个h*w的公告牌，h是高度，w是宽度，一个单位高度1为一行，然后会有一些公告贴上去，公 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22751.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22751.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 09 Nov 2012 02:20:52 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[行车(a1*b1+a1*b2+..a1*bn+a2*b1+...an*bn=(a1+..an)(b1+..bn) )]]></title>
      <description><![CDATA[ 		行车
(bicycle.pas/cpp)
题目描述
骑在自行车上，让微风追逐着他衣角，在不经意间捕获着一颗颗芳心，骄 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22750.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22750.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 09 Nov 2012 02:15:45 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[uva_10115-Automatic Editing]]></title>
      <description><![CDATA[ 		cpp 
/**本题含义是将前一个串转化为后一个串，当前一个串
 *完全找不到后，再去比较下一个串，直到所 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22749.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22749.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 09 Nov 2012 01:38:50 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[uva_340 - Master-Mind Hints]]></title>
      <description><![CDATA[ 		cpp
/**本题的意思是，对应相等的为强，不对应相等的为弱，
 * 我的做法是每次比较时复制一个目标串， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22748.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22748.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 09 Nov 2012 01:21:39 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[uva_10815-Andy&#039;s First Dictionary]]></title>
      <description><![CDATA[ 		cpp 
/*就是一个结构体计数加排序*/ 
#include &amp;lt;cstdio&amp;gt; 
#include &amp;lt;cstring&amp;gt; 
#include &amp;lt;iostream ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22747.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22747.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 09 Nov 2012 01:15:55 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[uva_10010-Where&#039;s Waldorf?]]></title>
      <description><![CDATA[ 		cpp
/**这里采用暴力法，首先将所有大写字母转化为小写，然后遍历整个矩阵，
 *搜索8个方向，获得搜索 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22746.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22746.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 09 Nov 2012 01:11:06 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 1394 Minimum Inversion Number（线段树，逆序数）]]></title>
      <description><![CDATA[ 		
题目大意：
给一个n个数的序列a1, a2, ..., an ，这些数的范围是0～n-1， 可以把前面m个数移动到后面去 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22745.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22745.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 09 Nov 2012 01:01:10 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ uva_10361-Automatic Poetry]]></title>
      <description><![CDATA[ 		cpp 
/**本题看懂题意就好解决了，就是把括号去掉输出一次，
 *然后交换字符串再输出一次
 */ 
#in ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22744.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22744.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 09 Nov 2012 00:53:42 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++中的向量（Vector）用法]]></title>
      <description><![CDATA[ 		C++中的向量（Vector）用法　　vector在C++标准模板库中的部分内容，它是一个多功能的，能够操作多种数据 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22743.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22743.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 08 Nov 2012 08:38:10 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[初窥函数指针]]></title>
      <description><![CDATA[ 		我们通常知道的都是用指针存储一个变量的地址，这个变量具有跟指针类型相同的数据类型。除了这个功能，指 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22741.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22741.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 08 Nov 2012 07:55:24 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj 3264 区间最值]]></title>
      <description><![CDATA[ 		cpp 
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt;string.h&amp;gt; 
#include&amp;lt;stdlib.h&amp;gt; 
#include&amp;lt;algorithm&amp;gt; 
#includ ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22742.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22742.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 08 Nov 2012 07:54:12 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Proc文件系统]]></title>
      <description><![CDATA[ 		一、Proc文件系统
Proc文件系统是一种在用户态检查内核态的机制，文件的内容是动态创建的，并不在磁盘上 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22740.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22740.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 08 Nov 2012 07:09:47 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[比赛(long double 与fixed)]]></title>
      <description><![CDATA[ 		比赛
 (mat.pas/c/cpp)
【问题描述】
    有两个队伍A和B，每个队伍都有n个人。这两支队伍之间进行n场 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22739.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22739.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 08 Nov 2012 05:43:46 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 4347 KD-TREE]]></title>
      <description><![CDATA[ 		KD-TREE#include&amp;lt;queue&amp;gt; 
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt;cstring&amp;gt; 
#include&amp;lt;algorithm&amp;gt; 
using namesp ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22738.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22738.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 08 Nov 2012 03:27:32 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[当C++遇到IOS应用开发之---List集合]]></title>
      <description><![CDATA[ 		    在Object-c中，数组使用NSArray和NSMutableArray(可变长数组)。使用语法如下：
cpp 
NSArray *ar ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22737.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22737.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 08 Nov 2012 02:59:58 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[排序算法系列：基数排序(Radix sort)（C语言）]]></title>
      <description><![CDATA[ 		通俗理解：结合计数排序，通过对待排数组中元素每一位进行排序，最终达到对整个数组排序的效果。观看动态 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22736.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22736.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 08 Nov 2012 01:11:27 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[排序算法系列：计数排序（Counting sort）（C语言）]]></title>
      <description><![CDATA[ 		通俗理解：通过将待排序中的数组与辅助数组的下标建立一种联系，辅助数组储存与自己下标相等的原数组的每 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22735.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22735.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 08 Nov 2012 01:00:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[各种版本的++、--原子操作]]></title>
      <description><![CDATA[ 		汇编实现（可内嵌在C++里使用）cpp 
#ifdef WIN32 
     void __inline atomic_inc(int* v) 
     { ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22734.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22734.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 07 Nov 2012 09:18:34 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Printf()输出格式控制]]></title>
      <description><![CDATA[ 		Printf()输出格式控制1．转换说明符
      %a(%A)     浮点数、十六进制数字和p-(P-)记数法(C99)
      ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22733.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22733.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 07 Nov 2012 09:16:27 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[原来结构体和函数是可以同名的]]></title>
      <description><![CDATA[ 		cpp 
#include &amp;lt;stdio.h&amp;gt; 
struct _func{ 
    int s; 
}; 
void _func(struct _func s) 
{ 
   ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22732.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22732.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 07 Nov 2012 09:13:22 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[http://acm.hdu.edu.cn/showproblem.php?pid=3308&amp;amp;amp;&amp;amp;amp;线段树之区间合并]]></title>
      <description><![CDATA[ 		由于这几天学算法的情绪高涨，于是就复习了之前学的线段树，这进一步加深了对线段树的理解，顺便记录一下 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22731.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22731.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 07 Nov 2012 08:33:13 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 3673 Cow Multiplication]]></title>
      <description><![CDATA[ 		一、题目信息
Cow Multiplication
Time Limit: 1000MS   Memory Limit: 65536K
Total Submissions: 10 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22730.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22730.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 07 Nov 2012 08:04:13 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[端口重用 C++（地址重用）]]></title>
      <description><![CDATA[ 		在以前的文章中，我曾经引用过一篇端口重用与端口独占程序设计。但是，后来我发现其中有一点写的不清楚， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22729.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22729.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 07 Nov 2012 05:06:42 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++拷贝构造函数和=赋值运算符详解]]></title>
      <description><![CDATA[ 		首先明确一点：系统已经提供了默认的 拷贝构造函数 和  =复制运算符。 即所谓的浅拷贝。但有时，我们必须 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22728.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22728.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 07 Nov 2012 05:05:50 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[海量用户积分排名算法探讨]]></title>
      <description><![CDATA[ 		问题
某海量用户网站，用户拥有积分，积分可能会在使用过程中随时更新。现在要为该网站设计一种算法，在 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22727.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22727.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 07 Nov 2012 05:03:15 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[SO_REUSEADDR例解]]></title>
      <description><![CDATA[ 		网友vmstat多次提出了这个问题：SO_REUSEADDR有什么用处和怎么使用。而
且很多网友在编写网络程序时也会 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22726.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22726.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 07 Nov 2012 02:46:52 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[前++和后++]]></title>
      <description><![CDATA[ 		对于内置数据类型:
目前编译器的优化水平，前++和后++没什么区别，通过汇编代码可以证明。对于自定义数据 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22725.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22725.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 07 Nov 2012 01:36:18 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[删除驱动符号链接出错-变量作用域和RtlInitUnicodeString的问题]]></title>
      <description><![CDATA[ 		摘要：NT式驱动中，在DriverUnload()中尝试删除之前创建的符号链接失败，最后发现原因是变量作用域和RtlI ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22724.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22724.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 07 Nov 2012 00:58:08 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ 动态创建控件——模仿windows记事本程序Part1]]></title>
      <description><![CDATA[ 		创建控件
　　正如创建所有其它的窗口一样，创建控件使用CreateWindowEx()这个API.将想要的已注册的类传 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22723.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22723.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 06 Nov 2012 09:10:33 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[qt操作Excel com方式]]></title>
      <description><![CDATA[ 		cpp 
//---------------------------------------------------------------------------------------- ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22722.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22722.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 06 Nov 2012 08:59:36 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[729 - The Hamming Distance Problem]]></title>
      <description><![CDATA[ 		cpp view plaincopyprint?
描述：和前面的几道水题一样，还是两种代码，使用库函数的话耗时比较少一点 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22720.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22720.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 06 Nov 2012 07:56:02 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ 当C++遇到IOS应用开发---SQLITE篇]]></title>
      <description><![CDATA[ 		   大约是一年多前开始接触OBJECT-C并进行IOS开发，一上来就被OBJECT里那种近似于&amp;amp;ldquo;丑陋&amp;amp;rdquo;的方 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22719.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22719.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 06 Nov 2012 07:41:28 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++标准库set类型]]></title>
      <description><![CDATA[ 		set容器只是单纯的键的集合，键必须为一。set容器不支持下标操作，而且没有定义maped_type类型。在set容器 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22718.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22718.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 06 Nov 2012 07:35:28 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++标准库：std_set作为一个有序集合]]></title>
      <description><![CDATA[ 		摘要：std::set作为标准库的一个关联容器，实现内部元素进行了排序，使用这特性可以对一组元素进行插入排 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22717.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22717.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 06 Nov 2012 07:01:28 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[c++中查询硬件与系统信息api]]></title>
      <description><![CDATA[ 		
ActivateKeyboardLayout 激活一个新的键盘布局。键盘布局定义了按键在一种物理性键盘上的位置与含义
B ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22716.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22716.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 06 Nov 2012 06:45:27 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 1757]]></title>
      <description><![CDATA[ 		a9,a8,a7,&amp;amp;hellip;,a0*
|f(0) 1 0 0,0,0,0,0,0,0|
|f(1) 0 1 0,0,0,0,0,0,0|
|f(2) 0 0 1,0,0,0,0,0 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22715.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22715.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 06 Nov 2012 05:17:47 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++中遍地New却不见delete疑问重重]]></title>
      <description><![CDATA[ 		在上篇博客中，大概了解了tinyxml工具的架构，那这篇博客，我们详细讲述如何利用tinyxml操纵xml。以及在操 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22714.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22714.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 06 Nov 2012 03:53:17 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Calculate the CDF of Poisson Distribution with Boost C++ Library]]></title>
      <description><![CDATA[ 		The Cumulative Distribution Function(CDF) of Poisson distribution can be easily calculated by R fu ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22813.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22813.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 06 Nov 2012 03:28:02 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ c++简单线程封装]]></title>
      <description><![CDATA[ 		模仿boost，用 tls 实现 interrupt 功能thread.hcpp 
#pragma once 
 
#include &amp;lt;windows.h&amp;gt; 
#inc ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22812.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22812.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 06 Nov 2012 02:35:28 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ AndEngine学习教程  ParticleSystem 粒子系统]]></title>
      <description><![CDATA[ 		1.本节要点
    本节主要基于粒子系统实现火焰视觉效果的模拟
2.新学习内容
   1.SpriteParticleSyste ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22811.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22811.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 05 Nov 2012 09:08:50 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[混合图 (hu误写成hqu……）]]></title>
      <description><![CDATA[ 		                         混合图
                   (dizzy.c/cpp/pas)
【问题描述】
    有一张N个 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22810.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22810.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 05 Nov 2012 08:55:19 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ C++开发那些dll和lib]]></title>
      <description><![CDATA[ 		  lib是编译时需要的，dll时运行时需要的。如果要完成源代码的编译，有lib就够了。如果也是动态连接的程序 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22809.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22809.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 05 Nov 2012 08:52:10 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[分割矩阵 (二分范围L,R)）]]></title>
      <description><![CDATA[ 		  分割矩阵
                   (browine.c/cpp/pas)
【问题描述】
    有N*M的一个非负整数矩阵。现在 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22808.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22808.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 05 Nov 2012 08:45:06 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ 无模态对话框]]></title>
      <description><![CDATA[ 		现在来看看CreateDialog()，它是DialogBox()的姐妹函数．区別在于DialogBox()拥有自己的消息循环并且直到 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22807.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22807.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 05 Nov 2012 07:35:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++标准库map类型]]></title>
      <description><![CDATA[ 		map是键-值对的集合。map类型通常可以理解为关联数组：可以使用键作为下标获取一个值，正如内置数组一样。 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22806.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22806.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 05 Nov 2012 06:10:49 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++标准库pair]]></title>
      <description><![CDATA[ 		与关联容器相关的模板类型,包含两个数据成员,在utility头文件中定义.pair类型提供的操作:pair&amp;lt;T1,T2&amp;gt; p1; ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22805.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22805.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 05 Nov 2012 03:46:46 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Google C++ 编程规范（1.1）]]></title>
      <description><![CDATA[ 		第一章  头文件第一节  #define保护所有头文件都应有#define保护以防止多次包含。包含符号的格式应为： &amp;lt; ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22804.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22804.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 05 Nov 2012 03:39:35 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[简单c++序列化]]></title>
      <description><![CDATA[ 		看了几个序列化框架，都有这个那个瑕疵1. boost  太大，不容易学2. eternity 不支持非侵入式，必须在类里 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22803.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22803.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 05 Nov 2012 02:55:12 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ poj1606-没想好就不要下手，否则浪费时间-模拟题的教训]]></title>
      <description><![CDATA[ 		这道题目题意很简单，就是给你两个容器，求出获得指定量水的步骤。
一看稍微分析就知道是广度优先搜索。 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22802.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22802.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 05 Nov 2012 02:22:34 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 3663 Power StationsDLX]]></title>
      <description><![CDATA[ 		题意：给你一个最多60个点150个边的无向图，每个点是一个村庄，每个村庄都有一个发电站，每个电站可以给它 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22801.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22801.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 05 Nov 2012 02:01:11 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ 算法设计：有n个数，范围是从1到n，且只有唯一的两个数相同，如何最快的求相同的这个数值？]]></title>
      <description><![CDATA[ 		为了方便问题描述，假设n = 10，即数组a10里有10个数，范围是从1到10，且里面只有两个数的值是相同的。 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22800.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22800.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 05 Nov 2012 01:03:42 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C/C++ 函数调用规范]]></title>
      <description><![CDATA[ 		以后技术方面的笔记也都记录在这个博客了.
今天做编译原理作业时遇到这个问题，就整理了下。参数的压栈、 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22798.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22798.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sun, 04 Nov 2012 00:12:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[线性表的顺序表示和实现]]></title>
      <description><![CDATA[ 		线性表是最常用且最简单的一种数据结构，一个线性表是 N 个数据元素的有限序列。顺序表存储结构能够容易的 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22799.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22799.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 03 Nov 2012 23:56:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++常考笔试题:不用if,while,do-while,for,打印出所有大于0小于k的整数.函数原型void printLess(int k);]]></title>
      <description><![CDATA[ 		笔试过程中左思右想,除了用定义一个类,利用其构造函数自动执行的特性来实现这个函数的功能,但是我想那样做 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22796.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22796.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 03 Nov 2012 23:46:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[修改AVI的录像尺寸]]></title>
      <description><![CDATA[ 		模糊的原因是RESIZE导致，所以可以适当地把录像尺寸改大（仅适合于 MJPEG），以减轻RESIZE的复作用。
  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22795.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22795.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 03 Nov 2012 23:28:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[杭电OJ——1079 Calendar Game]]></title>
      <description><![CDATA[ 		Calendar GameProblem Description
Adam and Eve enter this year&amp;amp;rsquo;s ACM International Collegiat ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22797.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22797.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 03 Nov 2012 22:34:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[杭电1081——to the max(动态规划和暴力法解)]]></title>
      <description><![CDATA[ 		To The Max
Problem Description
Given a two-dimensional array of positive and negative integers,  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22793.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22793.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 03 Nov 2012 22:18:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++之static静态修饰符详解]]></title>
      <description><![CDATA[ 		静态类成员：是那些与类本身有关的成员数据和成员函数，而不是与该类对象相关的成员数据和成员函数。
   ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22792.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22792.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 03 Nov 2012 22:08:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[进程退出方式]]></title>
      <description><![CDATA[ 		进程退出分为正常退出和异常退出两种：（1）正常退出
a.在main函数中执行return
b.调用exit函数
c.调用 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22794.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22794.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 03 Nov 2012 21:32:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 3613 Best Reward(拓展KMP求前缀回文串)]]></title>
      <description><![CDATA[ 		
题目大意：
给个字符串S，要把S分成两段T1,T2，每个字母都有一个对应的价值，如果T1，T2是回文串（从左 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22791.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22791.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 03 Nov 2012 05:03:39 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ POJ 2012金华邀请赛 (持续更新)]]></title>
      <description><![CDATA[ 		第一题，水题，但是题目读了很久，英语功底果然很差，主要是第二次排序的时候是按位排序，先按个位从小到 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22790.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22790.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 03 Nov 2012 03:48:25 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ RTP实时音视频数据传输,发送端和接收端]]></title>
      <description><![CDATA[ 		1.项目前期工作（配置好环境）
2.发送端文件编写（见下面的send.cpp）
3.接收端文件编写（见下面的rece ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22789.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22789.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 03 Nov 2012 02:36:46 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[10167 - Birthday Cake]]></title>
      <description><![CDATA[ 		cpp 
描述：我是完全把圆边缘的点都算出来，放到一个数组里，然后查询就可以了 
 
#include &amp;lt;iostre ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22788.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22788.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 03 Nov 2012 01:15:02 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Doxygen按原始注释输出（保留空格和换行）]]></title>
      <description><![CDATA[ 		在Doxygen注释中，我们经常需要用空格加上符号来描述一种结构图，但是因为Doxygen默认忽略空格和换行，因 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22787.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22787.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 02 Nov 2012 08:56:44 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ HDU4452 Running Rabbits]]></title>
      <description><![CDATA[ 		2012 Asia JinHua Regional Contest
Problem K. Running Rabbits
官方解题报告：
简单模拟，水题。
 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22786.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22786.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 02 Nov 2012 08:00:52 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ 非递归，按序输出集合的全排列]]></title>
      <description><![CDATA[ 		题目描述
非递归，按序输出集合全排列，是在笔试面试中经常考的问题。递归输出集合的全排列相对来说还是 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22785.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22785.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 02 Nov 2012 07:24:07 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ARM嵌入式编程（无操作系统、基于MDK）之最简单的程序:点亮一个LED灯]]></title>
      <description><![CDATA[ 		1.设计要求    EM-STM3210E开发板上有一个LED灯D1，编写程序点亮该灯。2.硬件电路连接    在开发板上，D1 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22784.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22784.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 02 Nov 2012 07:20:43 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ 关于大数据批量更新的问题(高性能)]]></title>
      <description><![CDATA[ 		当你批量操作数据的时候，常常会使用到update table1 from table2）的这种方式。这种方式是最简洁的。但当 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22783.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22783.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 02 Nov 2012 07:17:57 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[富翁和陌生人换钱游戏]]></title>
      <description><![CDATA[ 		cpp  阿
上机内容：富翁与陌生人换钱游戏 
 
上机目的：富翁与陌生人换钱游戏 
 * Copyright (c) 2 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22782.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22782.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 02 Nov 2012 07:08:06 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ HDU4442 Physical Examination]]></title>
      <description><![CDATA[ 		2012 Asia JinHua Regional Contest
Problem A. Physical Examination
官方解题报告：
对排在相邻的两 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22781.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22781.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 02 Nov 2012 06:53:31 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU4447 Yuanfang, What Do You Think?]]></title>
      <description><![CDATA[ 		2012 Asia JinHua Regional Contest
Problem F. Yuanfang, What Do You Think?
官方解题报告：
手工或 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22780.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22780.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 02 Nov 2012 05:38:27 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++解析xml利器—tinyxml图解法]]></title>
      <description><![CDATA[ 		在上篇博客中，提到了解析xml，作为一名实在的java程序猿。在java中解析xml方法有dom以及sax。习惯dom的我 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22779.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22779.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 02 Nov 2012 05:33:03 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[CF 241C Mirror Box]]></title>
      <description><![CDATA[ 		Bayan 2012-2013 Elimination Round (ACM ICPC Rules, English statements好悲剧的CF啊，怒拿#105，结果前 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22778.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22778.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 02 Nov 2012 03:29:08 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[继承与遮掩问题]]></title>
      <description><![CDATA[ 		继承与遮掩问题继承：
pure virtual 函数的目的是为了让Derived class 只继承函数接口。
impure virtua ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22777.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22777.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 02 Nov 2012 03:01:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[1+2+3+....+19+20=?]]></title>
      <description><![CDATA[ 		cpp 
上机内容：1+2+3+......+19+20 
 
上机目的：了解for用法 
 * Copyright (c) 2012, 烟台大学计 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22776.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22776.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 02 Nov 2012 02:39:10 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[乘法口诀表]]></title>
      <description><![CDATA[ 		cpp 
01./*     
02.* Copyright (c) 2012, 烟台大学计算机学院     
03.* All rights reserved.    ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22775.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22775.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 02 Nov 2012 02:35:09 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Incomplete type与Foreward declaration]]></title>
      <description><![CDATA[ 		有时我们在编程时会遇到一些与类型不完整有关的编译器报错，此时我们往往只是简单的把它改成相应的完整类 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22774.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22774.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 02 Nov 2012 02:08:19 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[uva_108 - Maximum Sum]]></title>
      <description><![CDATA[ 		cpp 
/**
 *  首先计算每一列的前序和（即0行到所有行上值的总和）
 *  其次，最大的子矩阵一定在a行 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22773.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22773.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 02 Nov 2012 02:05:48 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[设置鼠标不同的外观]]></title>
      <description><![CDATA[ 								 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22772.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22772.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 02 Nov 2012 01:53:53 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 2159 FATE （二维DP）]]></title>
      <description><![CDATA[ 		题意：一种游戏，杀一个怪需要消耗一定的忍耐度才能得到经验。现在需要n经验才能升级，共有m的忍耐度。其 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22771.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22771.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 01 Nov 2012 09:07:48 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 4443 Lost 2012 ACM/ICPC 金华区域赛B题]]></title>
      <description><![CDATA[ 		这题太恶心了。。。应该是我做过的最难的树形dp，那个圈超恶心。。。区域赛的时候只有两个队过了这道题， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22770.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22770.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 01 Nov 2012 09:03:09 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ 错排详解]]></title>
      <description><![CDATA[ 		错排问题一个寝室有四个人，过节时，每个人都会送出一封贺卡，假如一个盒子里有四封贺卡，寝室的每个成员 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22769.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22769.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 01 Nov 2012 08:55:10 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C/C++关键字static,const,inline,define,typedef]]></title>
      <description><![CDATA[ 		一 static1) 产生背景
引出原因：函数内部定义的变量，在程序执行到它的定义处时，编译器为它在栈上分配 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22768.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22768.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 01 Nov 2012 06:50:09 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C/C++语言实现动态数组]]></title>
      <description><![CDATA[ 		C数组的小问题
     这里说的动态数组是可以根据需要动态增长占用内存的数组，比如程序初始分配了100个元 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22767.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22767.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 01 Nov 2012 06:46:47 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[c++中常见问题]]></title>
      <description><![CDATA[ 		c++中常见问题
1、c++变量初始化规则
内置类型变量是否初始化决定于变量的定义位置，在函数体外定义的变 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22766.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22766.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 01 Nov 2012 06:37:13 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++内存分配]]></title>
      <description><![CDATA[ 		    自己在处理C++内存分配上的一点心得，如果有错误，欢迎大家指出。
      变量和对象在内存中的分配都 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22765.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22765.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 01 Nov 2012 03:52:50 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[分布排序（distribution sorts）算法大串讲]]></title>
      <description><![CDATA[ 		分布排序（distribution sorts）算法大串讲本文内容框架：&amp;amp;sect;1 鸽巢排序（Pigeonhole）&amp;amp;sect;2 桶排序 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22764.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22764.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 01 Nov 2012 03:35:35 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C_C++ 各种计时函数]]></title>
      <description><![CDATA[ 		 对Windows平台下常用的计时函数进行总结，包括精度为秒、毫秒、微秒三种精度的5 种方法。分为在标准C/C+ ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22862.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22862.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 01 Nov 2012 03:33:44 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ zoj 3587 Marlon&#039;s String(拓展KMP+dp)]]></title>
      <description><![CDATA[ 		
题目大意：
给字符串S，T，   找到所有的tetrad (a,b,c,d)， Sa..b + Sc..d = T , a&amp;amp;le;b and c&amp;amp;le;d. ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22861.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22861.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 01 Nov 2012 03:16:10 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[求1000以内的偶数和！方法二！]]></title>
      <description><![CDATA[ 		cpp
01./*  
02. * Copyright (c) 2012, 烟台大学计算机学院  
03.* All rights reserved.  
04.*  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22860.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22860.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 01 Nov 2012 02:54:31 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[求1000以内的偶数和！方法3]]></title>
      <description><![CDATA[ 		cpp 
01.01./*   
02.02. * Copyright (c) 2012, 烟台大学计算机学院   
03.03.* All rights reserv ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22859.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22859.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 01 Nov 2012 02:41:26 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ C++局部变量详解（笔试题）]]></title>
      <description><![CDATA[ 		最近参加了很多公司的笔试和面试，经常会遇到这样一个问题。如下：
cpp  
char* MyCopy(char *str)  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22858.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22858.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 01 Nov 2012 01:51:43 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 3374 String Problem(最小最大表示法+KMP)]]></title>
      <description><![CDATA[ 		题目大意：
给定一个字符串S， 可以通过向左移位得到另一个字符串。例如，S=&amp;quot;SKYLONG&amp;quot;, 通过位移得到的所 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22857.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22857.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 01 Nov 2012 01:03:23 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj3628-DFS/0-1背包-DP/枚举-数据比较弱、方法比较多]]></title>
      <description><![CDATA[ 		因为数据范围20，所以直接枚举是2^20，不会超时。直接求组合就行。在N个数里面取1个数，2个数。。。。N个 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22856.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22856.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 01 Nov 2012 00:43:39 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[sprintf函数详解]]></title>
      <description><![CDATA[ 		函数功能：
　　把格式化的数据写入某个字符串
头文件：
　　stdio.h
函数原型：
　　int sprintf(  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22855.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22855.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 31 Oct 2012 09:08:15 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[TC SRM 559 DIV1]]></title>
      <description><![CDATA[ 		果然没有适妞，TC是要掉RP的，呜呜开场不顺啊，貌似TC arena出了一点问题，不能用有道，而且不能复制粘贴 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22854.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22854.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 31 Oct 2012 08:29:11 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[求1000以内的偶数和！！方法一！]]></title>
      <description><![CDATA[ 		cpp
/* 
 * Copyright (c) 2012, 烟台大学计算机学院 
* All rights reserved. 
* 作    者： 王立 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22853.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22853.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 31 Oct 2012 08:28:33 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[求和式 (C++ 坑爹的&amp;amp;lt;&amp;amp;lt;,&amp;amp;gt;&amp;amp;gt;,%lld)]]></title>
      <description><![CDATA[ 		求和式(x3)
题目描述
作为本场考试的第一题，你的任务十分简单：
给定长度为n的序列Ai，求所有Aix ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22852.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22852.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 31 Oct 2012 08:02:02 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ POJ 1006]]></title>
      <description><![CDATA[ 		解题思路：中国剩余定理a &amp;amp;equiv; B1(mod m1)  a &amp;amp;equiv; B2(mod m2)  
........  
a &amp;amp;equiv; B ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22851.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22851.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 31 Oct 2012 06:59:21 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 4399 不错的线段树]]></title>
      <description><![CDATA[ 		Query
Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Tota ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22850.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22850.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 31 Oct 2012 06:30:17 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdoj1863畅通工程]]></title>
      <description><![CDATA[ 		思路：  因为之前做了一道题叫还是畅通工程（hdoj1233），题意几乎一样，我用的普利姆算法，只在原程序的 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22849.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22849.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 31 Oct 2012 06:29:29 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdoj2734Quicksum]]></title>
      <description><![CDATA[ 		超级水题不解释。cpp 
#include&amp;lt;iostream&amp;gt; 
#include&amp;lt;string.h&amp;gt; 
using namespace std; 
 
void m ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22848.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22848.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 31 Oct 2012 06:11:55 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdoj2570迷瘴]]></title>
      <description><![CDATA[ 		思路： 题意说只要配出的药水浓度低于给定值即可解毒，并要求求能解毒的药水的最大体积 我觉得这是个贪心 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22847.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22847.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 31 Oct 2012 06:11:19 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[uva_102 - Ecological Bin Packing]]></title>
      <description><![CDATA[ 		cpp 
/**本题是求最少移动次数，即比较第一个箱子中的相同颜色瓶子数量，不移动瓶子最多的那个，
  * ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22846.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22846.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 31 Oct 2012 05:31:20 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ubuntu中安装使用C、C++编译器gcc、g++]]></title>
      <description><![CDATA[ 		在windows上，很多人习惯用VC或者Visual Studio写代码和编译，那么在ubuntu中有什么工具可以编译C++代码呢 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22845.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22845.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 31 Oct 2012 05:06:37 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[快速会用c++异常捕获机制（一个程序几行代码）]]></title>
      <description><![CDATA[ 		整理了网上流传的经典三角形代码，添加了自己理解的内容。最终一个目的，就是先会用c++中的try  catch 块 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22844.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22844.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 31 Oct 2012 05:00:22 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[c++标准异常类的继承实现]]></title>
      <description><![CDATA[ 		出处来自百度。查来学习之用// AbnomalTest.cpp : 定义控制台应用程序的入口点。
#include &amp;quot;StdAfx.h&amp;quot;
 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22843.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22843.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 31 Oct 2012 03:21:30 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 4435 charge-station(12年天津)]]></title>
      <description><![CDATA[ 		题目：给出N个城市，从1开始需要遍历所有点，选择一些点建立加油站，使得花费最少http://acm.hdu.edu.cn/ ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22842.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22842.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 31 Oct 2012 02:43:02 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[设计和输出一个钻石图形]]></title>
      <description><![CDATA[ 		/* 
* 程序的版权和版本声明部分: 
* Copyright (c) 2012, 烟台大学计算机学院 
* All rights reserve ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22841.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22841.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 31 Oct 2012 00:49:12 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[利用C++求解一元二次方程]]></title>
      <description><![CDATA[ 		题目：求解一元二次方程：ax&amp;amp;sup2;+bx+c=0 的解，其中a=1,b=-3,c=2.
       分析：大家都知道一元二次方 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22840.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22840.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 30 Oct 2012 08:34:29 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++中的引用]]></title>
      <description><![CDATA[ 		学过C语言的都知道，学好C语言必须要学好指针，指针可以说成是内存中的一个地址，但是在C++中，指针的地位 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22839.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22839.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 30 Oct 2012 08:31:40 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ c++中 接口]]></title>
      <description><![CDATA[ 		面向对象的语言诸如JAVA提供了Interface来实现接口，但C++却没有这样一个东西，尽管C++ 通过纯虚基类实现 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22838.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22838.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 30 Oct 2012 05:47:21 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[c++中dll介绍（详细）]]></title>
      <description><![CDATA[ 		比较大的应用程序都由很多模块组成，这些模块分别完成相对独立的功能，它们彼此协作来完成整个软件系统的 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22837.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22837.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 30 Oct 2012 05:42:35 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ 解决ie6中fixed不起作用的问题]]></title>
      <description><![CDATA[ 		有时需要把一个元素固定在页面的某个部位，一般的解决方法是：&amp;lt;div class=&amp;quot;box&amp;quot;&amp;gt;&amp;lt;/div&amp;gt;.box{position:fix ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22835.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22835.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 30 Oct 2012 03:50:04 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ poj 4451 Dressing 一个小模拟 金华regional]]></title>
      <description><![CDATA[ 		cou,cou1分别记录clothes 和shoe的重复次数，自己花一下图就好啦
cpp 
#include&amp;lt;iostream&amp;gt; 
#in ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22834.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22834.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 30 Oct 2012 03:25:45 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ C/C++ SOAP工具包 gSOAP]]></title>
      <description><![CDATA[ 		gSOAP一种跨平台的C和 C++软件开发工具包。生成C/C++的RPC代码，XML数据绑定，对SOAP Web服务和其他应用形 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22833.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22833.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 30 Oct 2012 01:53:20 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[杭电OJ 1083——courses（二分图的匹配问题！匈牙利算法解答）]]></title>
      <description><![CDATA[ 		
Problem Description
Consider a group of N students and P courses. Each student visits zero, one ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22832.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22832.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 30 Oct 2012 01:36:01 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 4433 locker（12年天津，DP）]]></title>
      <description><![CDATA[ 		题目：给出两个串，每次可以选择连续的1-3个数字，进行同时加1或者同时减1，问最少经过多少次操作，将一个 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22831.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22831.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 30 Oct 2012 01:21:13 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ 用代码和UML图化解设计模式之《装饰模式》]]></title>
      <description><![CDATA[ 		这个模式看了两次，因为我有点不太理解，其实到现在也不太理解。通过写代码，自我理解就是把对象重新装饰 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22830.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22830.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 30 Oct 2012 00:50:20 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 2492]]></title>
      <description><![CDATA[ 		
树状数组。区间求出前当前i 的一段比ai能力值小的，和后一段比ai能力值小的人的个数。cpp 
#inc ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22829.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22829.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 08:38:27 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu2100Lovekey 字符串加法]]></title>
      <description><![CDATA[ 		hdu2100使用strcpy可以提高效率
cpp
#include&amp;lt;iostream&amp;gt; 
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt;cstdlib&amp;gt; 
 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22828.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22828.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 08:04:51 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ c++中的全局变量]]></title>
      <description><![CDATA[ 		关于ｃ＋＋中的全局变量就是说，遇到的问题是：想在两个．ｃｐｐ文件中，使用一个变量的值不变可以这样做 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22827.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22827.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 06:34:03 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[二叉树的基本操作]]></title>
      <description><![CDATA[ 		由于岗位实践需要，故写了一个树的基本操作，包括先，中，后序递归和非递归，计算高度，计算左子树个数， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22826.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22826.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 05:59:28 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ zoj 3329 One Person Game 概率dp（有环）]]></title>
      <description><![CDATA[ 		自己看了很多blog才弄明白，自己就不说什么啦，建议在做几道简单题再做这道题，我认为这个blog写的很好， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22825.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22825.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 05:31:41 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ poj3281-最大流]]></title>
      <description><![CDATA[ 		题目开始以为可以用二分匹配解决，但是要和两边都求最大匹配，没办法解决。但是想到最大流可以解决二分匹 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22824.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22824.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 05:29:14 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++学习 POJ3032 CARD TRICK]]></title>
      <description><![CDATA[ 		题意：我们要利用n张牌表演一个魔术，魔术的步骤是这样的：
将开头一张牌移动到最后，接着拿出这堆牌的第 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22823.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22823.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 03:57:31 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++ 使用delete删除指针(1)]]></title>
      <description><![CDATA[ 		众所周知，最开始我们用new来创建一个指针，那么等我们用完它之后，一定要用delete将该指针删掉。但是，值 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22821.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22821.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 03:44:44 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++ 使用delete删除指针(2)]]></title>
      <description><![CDATA[ 		从监视窗口中，我们可以看见虽然程序的第8行已经将指针p删除了，但是在监视窗口中p仍然存在，只是*p所指向 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22822.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22822.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 03:42:26 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj 3294 Life Forms 后缀数组求至少出现在K个字符串中的最长公共子串]]></title>
      <description><![CDATA[ 		  此题就是给出N个字符串，然后求一个最长的子串，它至少出现在N/2+1个字符串中，
如果有多个这样的子串 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22820.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22820.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 03:31:39 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 3068 最长回文 Manacher算法]]></title>
      <description><![CDATA[ 		   该题就是求一个字符串的最长回文子串，就是一个满足本身是回文的最长的子串。
   该题貌似可以用后缀 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22819.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22819.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 03:25:18 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[二分查找的 C++ 实现]]></title>
      <description><![CDATA[ 		只是作为 stdlib 中的 bsearch 的一个拓展吧，看看声明：
void *bsearch(const void*key, const void *b ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22818.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22818.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 02:56:55 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++异常之异常说明]]></title>
      <description><![CDATA[ 		为了能够编写适当的catch子句，了解一个函数是否抛出异常或会抛出哪些异常对函数的用户来说是很有帮助的。 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22817.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22817.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 02:46:57 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[使用C++和Windows API操作基于http协议的xml service]]></title>
      <description><![CDATA[ 		在S1死程群@kula的鼓励下，我开始使用kula提供的api来操作那个傻逼的&amp;amp;ldquo;鸟窝&amp;amp;rdquo;网站（https://ww ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22816.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22816.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 02:32:27 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[串的堆式存储结构]]></title>
      <description><![CDATA[ 		在C和C++语言中 ，提供一个称之为&amp;amp;ldquo;堆&amp;amp;rdquo;的共享空间，可以在程序运行过程中，系统利用函数mallo ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22815.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22815.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 02:28:35 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[多维动态数组]]></title>
      <description><![CDATA[ 		《C++  Primer》中说：在C++中没有多维数组，只有元素师数组的数组。
如：要想创建一个二维整数数组，首 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22814.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22814.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 01:24:05 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[连续背包 (背包套背包）]]></title>
      <description><![CDATA[ 		【问题描述】
从T组物品中选出一些物品，放入背包中，求剩余空间的最小值。
限制条件：从每组物品中挑选 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22912.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22912.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 29 Oct 2012 01:05:18 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[链表的插入 删除 排序 倒叙]]></title>
      <description><![CDATA[ 		cpp view plaincopy
#include &amp;lt;iostream&amp;gt; 
using namespace std; 
#include &amp;lt;stdio.h&amp;gt; 
#include &amp;lt; ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22911.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22911.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sun, 28 Oct 2012 01:03:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[找出100~200间的素数]]></title>
      <description><![CDATA[ 		/* 
* 程序的版权和版本声明部分: 
* Copyright (c) 2012, 烟台大学计算机学院 
* All rights reserve ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22905.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22905.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 27 Oct 2012 00:52:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[练习 c++ 特殊容器、特殊函数的使用]]></title>
      <description><![CDATA[ 		//specialcontainer.cppcpp
/*一般容器：stack,queue
 
特殊容器：priority_queue
 
.push(elemen ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22901.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22901.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 27 Oct 2012 00:49:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[循环结构的程序 求π的值]]></title>
      <description><![CDATA[ 		/* 
* 程序的版权和版本声明部分: 
* Copyright (c) 2012, 烟台大学计算机学院 
* All rights reserve ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22904.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22904.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 27 Oct 2012 00:40:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[使用动态数组]]></title>
      <description><![CDATA[ 		1、定义一个指针类型
如：typedef   double*   DoubleArrayPtr；
2、声明一个指针变量
如： DoubleArr ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22903.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22903.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 27 Oct 2012 00:39:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU OJ 1754 I Hate It 线段树之求区间最值]]></title>
      <description><![CDATA[ 		题意：说的很清楚，不必过多的解释了&amp;amp;hellip;&amp;amp;hellip;
思路：线段树的求区间最值&amp;amp;hellip;&amp;amp;hellip;解释在 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22909.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22909.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 27 Oct 2012 00:29:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[scnaf使用格式化字符串%d接受小数的情况]]></title>
      <description><![CDATA[ 		在使用scanf的时候，因为需要传递整数，所以，很显然格式化字符串使用&amp;amp;ldquo;%d&amp;amp;rdquo;，但是在测试的时候 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22908.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22908.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 27 Oct 2012 00:18:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++11老关键字的新含义(auto, using，extern)]]></title>
      <description><![CDATA[ 		C++11对关键字进行了修订，加入了nullptr、constexpr、decltype、default、static_assert等，同时原有的关 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22899.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22899.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 27 Oct 2012 00:07:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[CF 237C (质数区间）]]></title>
      <description><![CDATA[ 		给定区间a,b 求l的最小值使a,b中任意长度为l的一段包含至少k个Prime
二分lcpp 
#include&amp;lt;cstdio&amp;gt; ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22898.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22898.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 27 Oct 2012 00:06:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[规律数组的打印]]></title>
      <description><![CDATA[ 		规律数组的打印
【北京直真笔试题】打印数组如下4*4数组，要求打印N*N的数组？1  12  11  102  13  16   ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22900.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22900.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 26 Oct 2012 23:38:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU OJ 1166 敌兵布阵 线段树之插点问线]]></title>
      <description><![CDATA[ 		题意：不用多说了&amp;amp;hellip;&amp;amp;hellip;
思路：一个入门的线段树插点问线，解释在代码里
AC代码：
cpp 
 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22902.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22902.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 26 Oct 2012 23:06:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[表达式求值]]></title>
      <description><![CDATA[ 		cpp
描述：思路很简单，优先级比较完的情况下，采用两个栈就可以完成了&amp;amp;hellip;&amp;amp;hellip; 
cpp 
#i ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22906.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22906.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 26 Oct 2012 23:04:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[个人所得税计算器]]></title>
      <description><![CDATA[ 		cpp 
上机目的：学会使用循环控制语句解决实际问题 
上机内容：编写多分支选择结构程序，根据个人月收 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22907.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22907.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 26 Oct 2012 23:04:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++使用localtime函数需要注意的地方]]></title>
      <description><![CDATA[ 		在处理时间时用到了localtime这个函数，将一个UTC时间转为本地时间：cpp
#include &amp;lt;time.h&amp;gt; 
time_t  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22910.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22910.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 26 Oct 2012 21:47:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[CF 237A (Cash)]]></title>
      <description><![CDATA[ 		题目大意：是一堆人来h点m分来超市买东西，同时可以有an位顾客买单，买单可认为1分钟以内完成，问至少有几 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22897.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22897.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 26 Oct 2012 04:59:10 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[找出大于一个数的最小回文数]]></title>
      <description><![CDATA[ 		cpp
#include &amp;lt;stdio.h&amp;gt; 
#include &amp;lt;stdlib.h&amp;gt; 
#include &amp;lt;string.h&amp;gt; 
 
/********************** ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22896.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22896.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 26 Oct 2012 03:44:31 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[设计模式:单件模式]]></title>
      <description><![CDATA[ 		参加了多场笔试，在笔试题目中偶尔会问什么单件模式。在网上搜了之后了解到这是设计模式中的一种设计方法 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22895.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22895.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 26 Oct 2012 03:05:24 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 4419]]></title>
      <description><![CDATA[ 		矩形面积并cpp
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt;algorithm&amp;gt; 
#define N 20010 
using namespace std;  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22894.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22894.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 26 Oct 2012 01:31:55 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[BYSBZ 2748(音量调节-01背包）]]></title>
      <description><![CDATA[ 		一定要读题啊！！
这题说的是&amp;amp;mdash;&amp;amp;mdash;每次一定换，没说前后不能到一个音量。cpp 
#include&amp;lt;cst ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22893.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22893.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 26 Oct 2012 01:20:59 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj 1469 COURSES (最大匹配)]]></title>
      <description><![CDATA[ 		题目意思:有N个学生和P门课程，让你判断能否构成最大匹配。先输入一个T，表示有T组测试数据；在输入N和P， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22892.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22892.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 26 Oct 2012 01:18:29 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Object-C中的Category]]></title>
      <description><![CDATA[ 		 Object-C中的Category其实是一种对于类的方法的扩充，有些类似于类的继承，但是和继承还是不一样的。下面 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22891.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22891.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 26 Oct 2012 00:48:44 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++中字符串I/O]]></title>
      <description><![CDATA[ 		可以使用cout和插入操作符&amp;lt;&amp;lt;来输出string对象，这和处理其他类型的数据是一样的；
可以使用cin和提取操作 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22890.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22890.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 25 Oct 2012 09:11:47 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[strcpy, strcmp, strlen, memcpy 实现]]></title>
      <description><![CDATA[ 		cpp
#include &amp;lt;assert.h&amp;gt; 
#include &amp;lt;string.h&amp;gt; 
#include &amp;lt;stdlib.h&amp;gt; 
#include &amp;lt;stdio.h&amp;gt; 
 
c ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22889.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22889.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 25 Oct 2012 08:30:46 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[memory 编程接口]]></title>
      <description><![CDATA[ 		在Linux系统中，一般有32位（4GB）的地址空间，进程的4GB内存空间被分为两个部分 &amp;amp;mdash; 用户空间与内核 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22888.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22888.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 25 Oct 2012 07:14:59 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[用代码和UML图化解设计模式之《桥接模式》]]></title>
      <description><![CDATA[ 		桥接模式就是 独立和实现相分离。不同的厂家生产不同的产品。。。。产品和厂家有这组合的关系。  上代码 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22887.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22887.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 25 Oct 2012 05:24:44 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ 一道算法题：求和为某正整数的所有正整数集合]]></title>
      <description><![CDATA[ 		应该是网易的一道题目？忘记在哪里看到的了。题目的要求是给定正整数M，求所有和为M的正整数集合。如M=5， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22886.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22886.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 25 Oct 2012 05:08:37 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu1021(Fibonacci Again)]]></title>
      <description><![CDATA[ 		cpp 
#include &amp;lt;iostream&amp;gt; 
#include &amp;lt;cstdio&amp;gt; 
using namespace std; 
int a1000010; 
int mai ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22885.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22885.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 25 Oct 2012 02:54:30 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ POJ 3270(Cow Sorting)]]></title>
      <description><![CDATA[ 		这题主要是交换时要求代价最小
先找到环   相同数字 与   同列 相连
1  第一行为起始序列   第二行为目 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22884.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22884.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 25 Oct 2012 02:38:54 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu1021]]></title>
      <description><![CDATA[ 		cpp
#include&amp;lt;iostream&amp;gt; 
#include&amp;lt;cstdio&amp;gt; 
 
int main() 
 
{ 
    int n; 
    while(scanf ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22883.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22883.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 25 Oct 2012 02:30:50 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Qt中16进制数据的QByteArray与QString的转换]]></title>
      <description><![CDATA[ 		背景介绍：最近在做Qt串口相关PC机软件的开发。于是涉及到很多IO的操作，而IO的接收经常会存放在QByteArr ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22882.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22882.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 25 Oct 2012 02:30:16 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 2035]]></title>
      <description><![CDATA[ 		cpp 
#include&amp;lt;iostream&amp;gt; 
#include&amp;lt;cstdio&amp;gt; 
 
int main() 
{ 
    int a, b, res; 
    while ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22881.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22881.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 25 Oct 2012 02:29:48 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++实现Huffman树]]></title>
      <description><![CDATA[ 		#include &amp;quot;stdafx.h&amp;quot;
#include &amp;lt;iostream&amp;gt;
using std::cout;
using std::cin;
using std::endl; //存 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22880.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22880.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 25 Oct 2012 02:13:16 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[《C++的设计与演化》读书笔记]]></title>
      <description><![CDATA[ 		&amp;lt;&amp;lt;C++的设计与演化&amp;gt;&amp;gt;原文摘录与自己翻译及注解
原文1：
1.Even though support of concurrency and Sim ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22879.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22879.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 25 Oct 2012 01:46:58 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 3094 Quicksum]]></title>
      <description><![CDATA[ 		一、题目信息
Quicksum
Time Limit: 1000MS   Memory Limit: 65536K
Total Submissions: 11249   Acce ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22878.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22878.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 24 Oct 2012 09:12:31 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[关于c++中虚函数和接口的关系区分（简单）]]></title>
      <description><![CDATA[ 		虚函数:                虚函数的作用是实现动态联编，也就是在程序的运行阶段动态地选择合适的成员函数， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22877.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22877.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 24 Oct 2012 07:49:51 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C/C++下使用SQLite轻量级数据库]]></title>
      <description><![CDATA[ 		最近公司研发组研发一个产品使用了这个轻量级的数据库，感觉的特别有趣，就初步看看。
一、SQLite
SQLi ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22876.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22876.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 24 Oct 2012 07:34:43 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++中类对象的内存布局和占用空间]]></title>
      <description><![CDATA[ 		很多C++书籍中都介绍过，一个Class对象需要占用多大的内存空间。最权威的结论是：
*非静态成员变量总合。 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22875.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22875.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 24 Oct 2012 07:25:17 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[JNA 调用 so 库]]></title>
      <description><![CDATA[ 		最近自己写的一个广告发布平台要迁移到Linux平台上，由于之前用的是windows平台的dll文件，现在要改用.so ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22874.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22874.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 24 Oct 2012 07:17:06 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[由点集序列或数组创建凸边形]]></title>
      <description><![CDATA[ 		cpp 
#include&amp;lt;cv.h&amp;gt; 
#include&amp;lt;highgui.h&amp;gt; 
#include&amp;lt;stdlib.h&amp;gt; 
 
#define ARRAY 0 
 
int ma ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22873.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22873.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 24 Oct 2012 07:08:55 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[c++学习笔记，文件读取，字符串相关]]></title>
      <description><![CDATA[ 		1.字符串比较函数int strcmp(char* str1,char*str2)当两个字符串相同时，返回0，（而matlab的strcmp返回1 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22872.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22872.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 24 Oct 2012 07:00:01 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj 2778 DNA Sequence AC自动机+矩阵快速冥]]></title>
      <description><![CDATA[ 		  题意很简单，假定文本集就是A,C,T,G，给定M个模式串，问你长度为N的文本不出现这些模式
串的可能性到底 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22871.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22871.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 24 Oct 2012 06:48:34 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hnu 2243 考研路茫茫——单词情结 AC自动机+矩阵冥累加和]]></title>
      <description><![CDATA[ 		这个题目更奇葩。据说是上一个题的加强版。
   题意是给定M个模式串，然后给定长度L，问不超过L的文本至 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22870.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22870.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 24 Oct 2012 06:23:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++实现链队列的基础操作]]></title>
      <description><![CDATA[ 		空队列：就是头指针和尾指针指向同一个空间。
插入元素，从队尾进，处理一下队尾，然后，若队列为空，注 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22869.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22869.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 24 Oct 2012 06:19:15 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++拷贝构造函数详解]]></title>
      <description><![CDATA[ 		. 什么是拷贝构造函数
首先对于普通类型的对象来说，它们之间的复制是很简单的，例如：
c-sharp 
in ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22868.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22868.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 24 Oct 2012 06:03:57 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[關於C++中數據類型的一些問題]]></title>
      <description><![CDATA[ 		在《C++ primer》一書中，將C++的數據類型分爲了兩大類，分別是整型和浮點型。其中整型包括整數，字符，和 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22867.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22867.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 24 Oct 2012 05:57:13 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj2028-水的一塌糊涂]]></title>
      <description><![CDATA[ 		直接上代码：还以为很麻烦呢。。。
 
cpp 
#include &amp;lt;stdio.h&amp;gt; 
#include &amp;lt;stdlib.h&amp;gt; 
#include &amp;lt; ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22866.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22866.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 24 Oct 2012 05:18:32 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[用代码和UML图化解设计模式之《创建者模式》]]></title>
      <description><![CDATA[ 		今天学习了建造者模式，目前较为复杂的一个模式之一。但是思考起来就觉得她很像抽象工厂的生产者模式。 但 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22865.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22865.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 24 Oct 2012 05:17:35 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 1007 DNA Sorting]]></title>
      <description><![CDATA[ 		一、题目信息
DNA Sorting
Time Limit: 1000MS   Memory Limit: 10000K
Total Submissions: 68122   A ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22864.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22864.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 24 Oct 2012 02:14:25 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[队列之出队入队]]></title>
      <description><![CDATA[ 		cpp 
 线性结构的俩种常见应用之二&amp;amp;mdash;&amp;amp;mdash;队列                                              ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22863.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22863.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 24 Oct 2012 01:55:54 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 1850 Code]]></title>
      <description><![CDATA[ 		  坐标都弄得我头晕。我先打表把以某字母开头长度为i的方案数都预先存储。然后再从输入的字符串里面分解： ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22961.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22961.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 19 Sep 2012 08:17:07 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ c++ 截取屏幕图片并保存]]></title>
      <description><![CDATA[ 		屏幕捕捉技术第一步就是抓取屏幕的桌面
虽然print screen键可以，但是在实际中就有点不适用了
下面的代 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22960.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22960.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 19 Sep 2012 07:56:35 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 2492 Ping pong 树状数组求逆序数]]></title>
      <description><![CDATA[ 		题意：给你一些不同数，求满足a &amp;lt; b &amp;lt; c的有多少组。
 代码：
cpp
#include &amp;lt;iostream&amp;gt; 
#include  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22959.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22959.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 19 Sep 2012 07:54:12 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 2845 Beans]]></title>
      <description><![CDATA[ 		思路：动态规划  对于一行来说，相邻的数不可同时取，容易得到状态转移方程：           dpi=max(dpi- ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22958.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22958.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 19 Sep 2012 05:04:32 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Head First_设计模式_学习笔记_第01章_策略模式]]></title>
      <description><![CDATA[ 		 
        第一次用这书来学习设计模式，还真是超正点，无意中学会了第一个设计模式&amp;amp;mdash;&amp;amp;mdash;策略模 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22957.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22957.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 19 Sep 2012 03:45:16 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdoj1003maxsum]]></title>
      <description><![CDATA[ 		大致题意：        输入一个数列，找到从哪个数到哪个数的和最大，即最大子串（区分于子序列）        输 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22956.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22956.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 19 Sep 2012 03:15:39 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ POJ 1014 Dividing]]></title>
      <description><![CDATA[ 		
思路：多重背包，以总价值sum为背包容量，当dpsum/2=sum/2时满足平分条件cpp 
#include&amp;lt;stdio.h&amp;gt;  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22955.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22955.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 19 Sep 2012 03:06:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[字符串的复制srcmsg---dstmsg]]></title>
      <description><![CDATA[ 		中午练习：
cpp 
include io32.inc 
.data 
     srcmsg byte &amp;amp;#39;This is a loop copy.&amp;amp;#39;,0  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22954.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22954.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 19 Sep 2012 01:56:48 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[4 Values whose Sum is 0]]></title>
      <description><![CDATA[ 		这个题目同上道二分的题目一样，只是把数字分成两堆，在排序用二分的思想，但是必须明白，不是在找到一个 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22953.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22953.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 19 Sep 2012 01:35:52 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 1195 Mobile phones 二维树状数组]]></title>
      <description><![CDATA[ 		题意：有一个N * N广场，广场里面有一些手机，某个格子是可以改变的，增加或者减少，问一个小矩阵内有多少 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22952.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22952.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 19 Sep 2012 01:33:59 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[uva 10034 - Freckles]]></title>
      <description><![CDATA[ 		题目意思：  给定n个点的坐标，要求找到最短的路径将这些点链接起来思路：  Prime + 最小生成树
分析：  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22951.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22951.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 19 Sep 2012 01:30:14 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[can you find it?]]></title>
      <description><![CDATA[ 		最近感觉二分压力超级大，所以和妹子一起做了二分的题目，好水的题目啊，可是没办法谁叫我们太弱了呢，继 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22950.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22950.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 19 Sep 2012 01:16:51 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ c++中string类字符串和c中char*/char型型字符串的区别]]></title>
      <description><![CDATA[ 		概念区分
在c中，是没有string类型的数据的。但是c语言里有&amp;lt;string.h&amp;gt;这个头文件。容易让人误认为c中有s ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22949.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22949.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 19 Sep 2012 01:12:08 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj1568 Find the Winning Move----Find the Winning Move极大极小搜索]]></title>
      <description><![CDATA[ 		ind the Winning Move
Time Limit: 3000MS   Memory Limit: 32768K
Total Submissions: 421   Accepted ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22948.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22948.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 19 Sep 2012 00:50:09 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ HDU 2844/POJ 1742 Coins]]></title>
      <description><![CDATA[ 		                  
思路：多重背包+二进制优化cpp
; 
int c110,v110,n,m,sum; 
int completep ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22947.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22947.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 18 Sep 2012 08:54:12 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ POJ 3321 Apple Tree 树状数组]]></title>
      <description><![CDATA[ 		题意：有一棵树，树上有一些叉，每个叉上刚开始都有一个苹果，对每个叉可以有两种操作，若刚开始有苹果， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22946.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22946.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 18 Sep 2012 08:43:58 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[UVa 10986 - Sending email (Dijkstra优化, SPFA)]]></title>
      <description><![CDATA[ 		题目：
Problem E
Sending email
Time Limit: 3 seconds
&amp;quot;A new internet watchdog is creating a st ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22945.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22945.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 18 Sep 2012 07:34:27 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[把二元查找树转变成排序的双向链表]]></title>
      <description><![CDATA[ 		cpp
&amp;lt;span style=&amp;quot;color: rgb(51, 51, 51); font-family: Arial; font-size: 14px; line-height: 26px ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22944.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22944.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 18 Sep 2012 07:25:18 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ UVa 10099 - The Tourist Guide(Floyd, 最大生成树)]]></title>
      <description><![CDATA[ 		
题目：
Problem D
The Tourist Guide
Input: standard input
Output: standard output
 
Mr. G.  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22943.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22943.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 18 Sep 2012 06:58:11 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[UVa 10048 - Audiophobia(Floyd, Kruskal)]]></title>
      <description><![CDATA[ 		题目：
  Problem B: Audiophobia Consider yourself lucky! Consider yourself lucky to be still brea ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22942.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22942.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 18 Sep 2012 06:14:19 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 2159 FATE]]></title>
      <description><![CDATA[ 		思路：二维背包
 
将经验看作价值有动态转移：dp i  j =max(dp i  j ,dp i-r k   j-1 +v ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22941.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22941.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 18 Sep 2012 06:01:15 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[UVa 567 - Risk （Floyd）]]></title>
      <description><![CDATA[ 		题目：  Risk
Risk is a board game in which several opposing players attempt to conquer the world. ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22940.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22940.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 18 Sep 2012 05:37:55 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[如何给线程函数 beginthread 和 pthread_create 传递参数]]></title>
      <description><![CDATA[ 		1. 传递单个参数：直接传递指向参数的指针。
/*----------------------- beginthread.c --------------- ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22939.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22939.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 18 Sep 2012 05:16:39 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[最小的K个数]]></title>
      <description><![CDATA[ 		问题描述：给定的n个整数，计算其中最小的K个数。
最直观的解法莫过于将n个数按升序排列后输出前k个。但 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22938.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22938.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 18 Sep 2012 05:14:29 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[虚基类、纯虚函数、抽象类]]></title>
      <description><![CDATA[ 		虚基类、纯虚函数和抽象类1、虚基类  
          在《多继承》中讲过的例子中，由类A，类B1和类B2以及类 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22937.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22937.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 18 Sep 2012 01:07:53 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 2181 Cows 树状数组]]></title>
      <description><![CDATA[ 		题意：有一些牛，这些牛有一个属性值，这个属性值的范围给出，为si,ei,若si &amp;lt;= sj &amp;amp;&amp;amp; ei &amp;gt;= ej &amp;amp;&amp;amp; ei - s ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22936.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22936.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 18 Sep 2012 00:59:03 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 4293 Groups（12年成都网络赛-DP）]]></title>
      <description><![CDATA[ 		题目链接：Click here~~
题意：
有 n 个人，可任意分成若干组，然后每个人各提供一个信息，表示他们组前 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22935.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22935.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 08:52:15 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 1176 免费馅饼]]></title>
      <description><![CDATA[ 		思路：据说是DP题(时间dp)    动态转移：dp i  j +=max(dp i+1  j-1 ,dp i+1  j ,dp i+1  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22934.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22934.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 08:19:26 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 1203 I NEED A OFFER!]]></title>
      <description><![CDATA[ 		思路：简单的01背包   总费用看作背包容量，申请费用看作每个背包的重量，价值为至少有一份offer的概率   ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22933.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22933.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 06:47:08 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 1069 Monkey and Banana]]></title>
      <description><![CDATA[ 		题意：把给定的长方体（不限）叠加在一起，叠加的条件是，上面一个长方体的长和宽都比下面长方体的长和宽 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22932.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22932.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 06:21:10 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ C++入门进阶之一： 基础知识介绍]]></title>
      <description><![CDATA[ 		1.  C++是1980年由贝尔实验室的Bjarne Stroustrup博士创立的语言
2.  C++语言最大的两个特点： 全面兼容 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22929.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22929.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 03:34:13 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ C++入门进阶之2： 函数]]></title>
      <description><![CDATA[ 		1.  函数在没有被调用时是静止的，此时的形参只是一个符号。 函数在被调用时才执行，也是在被调用时，才由 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22930.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22930.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 03:33:14 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++入门进阶之3： 类和对象]]></title>
      <description><![CDATA[ 		1. 面向对象的四个主要特征:  抽象， 封装， 继承，多态 2. 与普通的函数不同， 类的成员函数需要在实现的 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22931.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22931.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 03:32:17 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[一个关于文件中位运算的的处理函数。]]></title>
      <description><![CDATA[ 		cpp 
函数ReadDat()的功能是实现从文件IN88.DAT中读取一篇英文文章存入到字符串数组xx中。请编制函数C ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22928.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22928.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 03:10:35 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 1807 Super Jumping! Jumping! Jumping!]]></title>
      <description><![CDATA[ 		一个最大上升子序列问题dpi 记录了在i之前且在i位置上的最大上升序列和，dpi等于前面aj&amp;lt;ai且dpj ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22927.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22927.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 02:37:14 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[SPOJ 1043 Can you answer these queries I（GSS1 线段树）]]></title>
      <description><![CDATA[ 		题目：查询区间最大子段和 简单线段树，可是写了好久~~~跪维护3个值，区间的最大子段和，左端连续的最大子 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22926.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22926.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 02:34:30 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ HDU 4260]]></title>
      <description><![CDATA[ 		简单递归cpp
#include&amp;lt;algorithm&amp;gt; 
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt;cstring&amp;gt; 
using namespace std;  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22925.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22925.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 02:14:33 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[广搜1 poj 2243]]></title>
      <description><![CDATA[ 		Knight Moves
Time Limit: 1000MS   Memory Limit: 65536K
Total Submissions: 8800   Accepted: 5051 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22924.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22924.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 02:12:58 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 2571 命运]]></title>
      <description><![CDATA[ 		
思路：dp i  j  + = ( dp i  k  , dp i - 1  j , dp i  j - 1 );( k 为 j 的真因子)c ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22923.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22923.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 02:04:49 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ zoj3513 Human or Pig----P/N分析 博弈]]></title>
      <description><![CDATA[ 		 Human or Pig
Time Limit: 2 Seconds      Memory Limit: 65536 KB
A man is lost in a strange world ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22922.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22922.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 02:02:46 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Wythoff Game(hdu2177)]]></title>
      <description><![CDATA[ 		对于某个局势(a,b)  ，b&amp;gt;=a
差值k=b-a
对于某个确定的k
有唯一的奇异局势（必败点） (a_k,b_k)   其中 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22921.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22921.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 01:57:37 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 4271]]></title>
      <description><![CDATA[ 		字符串的编辑距离的扩展
cpp
#include&amp;lt;algorithm&amp;gt; 
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt;cstring&amp;gt; 
using  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22920.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22920.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 01:56:08 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[字符串转化为数字]]></title>
      <description><![CDATA[ 		将给定字符串转化为数字，如果结果为正较大返回2147483647，如果结果为负且较大返回-2147483648。字符串除 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22919.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22919.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 01:37:32 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ HDU 2084 数塔]]></title>
      <description><![CDATA[ 		
简单的贪心思想：把最大的数添加进来sij+=max(si+1j,si+1j+1);cpp
#include&amp;lt;stdio.h&amp;gt;  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22918.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22918.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 01:23:57 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ HDU1505/POJ1964 City Game]]></title>
      <description><![CDATA[ 		和HDU 1506类似，用aij表示  在i高度j位置上的最大高度 cpp
#include&amp;lt;stdio.h&amp;gt; 
#define N 1002  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22917.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22917.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 01:21:53 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 3278(BFS-搜索范围）]]></title>
      <description><![CDATA[ 		这题是BFS水的
主要是范围
0&amp;lt;=n,k&amp;lt;=100000  但是有可能搜到200000&amp;amp;hellip;&amp;amp;hellip;
半天功夫才A.delp ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22916.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22916.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 01:00:37 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 4276 树形DP + 分组背包]]></title>
      <description><![CDATA[ 		题意：一棵树，让你在规定时间Ｔ内从１号节点走到ｎ号节点，并取得最多的宝藏值。
很容易可以想到一个这 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22915.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22915.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 17 Sep 2012 00:59:49 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 1506 Largest Rectangle in a Histogram]]></title>
      <description><![CDATA[ 		
重点：从左到右，对于每个点，记算出他所能向左和向右延伸的最大边界cpp 
#include&amp;lt;stdio.h&amp;gt; 
__in ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22913.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22913.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sun, 16 Sep 2012 00:41:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[zoj2686 Cycle Game---dfs 找规律 博弈]]></title>
      <description><![CDATA[ 		Cycle Game
Time Limit: 5 Seconds      Memory Limit: 32768 KB
Here is a game played on a cycle by ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23011.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23011.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sun, 16 Sep 2012 00:40:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 3256(SPFA）]]></title>
      <description><![CDATA[ 		这题只能对每一个点查一遍&amp;amp;hellip;&amp;amp;hellip;
有向图的话能用floyd，可是迫于时限用了SPFA。
delphi 
 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23009.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23009.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sun, 16 Sep 2012 00:38:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++入门进阶之一： 基础知识介绍]]></title>
      <description><![CDATA[ 		1.  C++是1980年由贝尔实验室的Bjarne Stroustrup博士创立的语言
2.  C++语言最大的两个特点： 全面兼容 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23008.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23008.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sun, 16 Sep 2012 00:26:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 3067 Japan 树状数组]]></title>
      <description><![CDATA[ 		题意：两边都有一些城市，从上到下排列，有些城市之间有路，路与路之间会形成交点，问最后会形成多少个交 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22914.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22914.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sun, 16 Sep 2012 00:11:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[zoj2290 Game----博弈 打表找规律]]></title>
      <description><![CDATA[ 		Game
Time Limit: 2 Seconds      Memory Limit: 65536 KB
Two players(A and B) take turns to take s ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23010.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23010.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sun, 16 Sep 2012 00:03:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C/C++函数调用的几种方式]]></title>
      <description><![CDATA[ 		我们知道，调用函数时，计算机常用栈来存放函数执行需要的参数，由于栈的空间大小是有限的，在windows下栈 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23007.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23007.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 15 Sep 2012 23:34:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU2955 Robberies]]></title>
      <description><![CDATA[ 		最重要的是找动态转移方程，可以将所用银行里的钱看作背包容量，每一家银行的钱看作重量，不被抓到的概率 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23006.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23006.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 15 Sep 2012 02:47:48 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[找出n个字符串中出现次数最多的子串]]></title>
      <description><![CDATA[ 		该程序未考虑出错机制，同时效率比较低。只是算法比较简单一些，比较容易理解。#include &amp;quot;stdafx.h&amp;quot;
#in ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23005.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23005.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 15 Sep 2012 01:38:05 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ POJ 3692（匈牙利算法）]]></title>
      <description><![CDATA[ 		delphi 
Program P3692; 
const 
   maxn=200; 
 
var 
   n,m,l,i,j,k,ans,x,y:longint; 
   b ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23004.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23004.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 15 Sep 2012 00:45:15 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ural 1471 Tree题解]]></title>
      <description><![CDATA[ 		注意本题可能会Crash。采用Color = 0 1 2 的解法，而不用Parent限制一棵树。某种情况下也可以用cpp ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23003.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23003.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 14 Sep 2012 08:52:06 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 4398 Template Library Management]]></title>
      <description><![CDATA[ 		贪心，每次找最远的删
#include&amp;lt;iostream&amp;gt; 
#include&amp;lt;vector&amp;gt; 
#include&amp;lt;algorithm&amp;gt; 
#include&amp;lt;cstdi ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23002.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23002.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 14 Sep 2012 08:35:43 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++数据类型之间转换集锦]]></title>
      <description><![CDATA[ 		字符类型间的转换：1、LPCWSTR-&amp;gt;wchar_t *;LPCSTR -&amp;gt;char *;LPCWSTR-&amp;gt;const  wchar_t *;2、string -&amp;gt;LPWS ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23001.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23001.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 14 Sep 2012 08:00:18 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ poj2599 A funny game---图的sg]]></title>
      <description><![CDATA[ 		A funny game
Time Limit: 1000MS   Memory Limit: 65536K
Total Submissions: 1654   Accepted: 692
 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23000.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23000.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 14 Sep 2012 07:01:06 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ poj3537 Crosses and Crosses----sg]]></title>
      <description><![CDATA[ 		Crosses and Crosses
Time Limit: 3000MS   Memory Limit: 65536K
Total Submissions: 1866   Accepted ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22999.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22999.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 14 Sep 2012 05:44:24 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 4275 Color the Tree 树的不重复染色 求树的中心+hash]]></title>
      <description><![CDATA[ 		题意：给定n（n&amp;lt;=50000）个点组成的树，用m（m&amp;lt;=100000）种颜色染色，问不重复（通过旋转）的染色方法数有 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22998.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22998.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 14 Sep 2012 05:03:37 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 4272]]></title>
      <description><![CDATA[ 		正解是状态压缩的搜索dfs求是否有可行解，bfs求最优解
cpp
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt;cstring&amp;gt; 
# ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22997.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22997.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 14 Sep 2012 03:47:24 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ Qt拷贝文件、文件夹（QFile::copy）]]></title>
      <description><![CDATA[ 		cpp 
//拷贝文件： 
bool MyTest007::copyFileToPath(QString sourceDir ,QString toDir, bool cover ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22996.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22996.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 14 Sep 2012 03:45:03 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 4392 Maximum Number Of Divisors]]></title>
      <description><![CDATA[ 		只跑了15ms，因为用了一个不能保证完全正确的剪枝，我猜想最优的情况一定能通过另一种最优的情况得到，即 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22995.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22995.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 14 Sep 2012 03:36:30 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 3252 Round Numbers]]></title>
      <description><![CDATA[ 		好久不写，这个题目又弄了几个小时，水平还是有限。   这道题我用组合数学来做，如果要求区间a,b的个数 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22994.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22994.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 14 Sep 2012 03:09:46 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ hust 1342 Cheat Secretly]]></title>
      <description><![CDATA[ 		题目大意：一个人，如果在一人点没有出边时，可以跳转到任意点，求最小跳转次数使得走完所有必走边。题目 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22993.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22993.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 14 Sep 2012 02:12:39 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[创建二叉树（递归）]]></title>
      <description><![CDATA[ 		非递归创建二叉树，需要用到栈，的确太烦了。这里只给出递归创建二叉树的方法。cpp 
#include &amp;quot;stdafx ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22992.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22992.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 14 Sep 2012 01:28:51 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj 3252 RoundNumber]]></title>
      <description><![CDATA[ 		 题意是求把十进制数转化成二进制数，0的个数大于等于1 的数，给定一个闭区间求出区间的这样的数有多少个 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22991.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22991.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 14 Sep 2012 00:55:21 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 2411 Mondriaan&#039;s Dream(状态压缩)]]></title>
      <description><![CDATA[ 		cpp 
/*
正常求解超时，然后打表通过。
自己定义状态，我的解法横木块0,0，竖木块1,0，其中1表示 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22990.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22990.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 14 Sep 2012 00:51:56 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[sgu 176. Flow construction]]></title>
      <description><![CDATA[ 		题目大意：网中有些边必须满流，求最小可行流题目思路：有上下界最小流，见周源《一种简易的方法求解流量 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22989.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22989.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 13 Sep 2012 09:16:57 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 2473 Junk-Mail Filter 并查集+设立虚父节点(马甲)]]></title>
      <description><![CDATA[ 		原题：
Problem Description
Recognizing junk mails is a tough task. The method used here consists ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22988.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22988.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 13 Sep 2012 08:22:59 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[数据结构---线性表]]></title>
      <description><![CDATA[ 		
测试代码
TestList.c
cpp
#include &amp;lt;stdio.h&amp;gt; 
#include &amp;quot;List.h&amp;quot; 
 
int main() 
{ 
    in ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22987.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22987.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 13 Sep 2012 07:03:28 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[二叉树]]></title>
      <description><![CDATA[ 		复习下二叉树，创建二叉树，分别以先序，中序，后续三种遍历访问二叉树，输出二叉树的叶子节点及叶子节点 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22986.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22986.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 13 Sep 2012 07:02:30 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 4028 The time of a day（11年上海 离散化DP）]]></title>
      <description><![CDATA[ 		题目：给出1-N这N个数，问有多少个子集，集合里的lcm是大于等于m的 
可以发现m的范围是很大的，而且1-N的 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22985.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22985.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 13 Sep 2012 06:48:07 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu3094 A tree game----树的删边游戏]]></title>
      <description><![CDATA[ 		A tree game
Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22984.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22984.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 13 Sep 2012 06:33:29 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ 开源项目之C++远程方法调用框架 RMI for C++]]></title>
      <description><![CDATA[ 		RMI for C++ 是一个专为 C++ 语言提供的远程方法调用框架，与 CORBA 不同的是，CORBA 适合不同的编程语言 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22983.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22983.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 13 Sep 2012 06:17:24 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[让控制台程序后台运行并开机启动的简单方法]]></title>
      <description><![CDATA[ 		写完了一个控制台程序，想把让它在后台运行，并开机自启动。有一种简单的方法如下。
1.后台运行
字一个 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22982.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22982.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 13 Sep 2012 06:11:17 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 2448]]></title>
      <description><![CDATA[ 		最短距离+二分图最优匹配。 先计算各个采矿点的最短距离。 同时题目也给出n个船的起始所在的位置。那么就 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22981.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22981.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 13 Sep 2012 05:52:22 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ HDU4273 Rescue（2012 ACM/ICPC Asia Regional Changchun Online）]]></title>
      <description><![CDATA[ 		三维凸包，贴模板过的，不解释&amp;amp;hellip;&amp;amp;hellip;cpp 
#include&amp;lt;iostream&amp;gt; 
#include&amp;lt;cmath&amp;gt; 
#includ ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22980.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22980.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 13 Sep 2012 05:47:31 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[整数划分（三连发）]]></title>
      <description><![CDATA[ 		第一题：1 样例：如一个正整数5，可以划分为7种：5
4,1
3,2 3,1,1
2,2,1 2,1,1,1
1,1,1 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22979.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22979.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 13 Sep 2012 05:36:02 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[开源项目之C++界面库 GLUI]]></title>
      <description><![CDATA[ 		GLUI是一个C++界面库，它提供了buttons, checkboxes, radio buttons, 等常用控件，以及OPENGL支持。GLUI界 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22978.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22978.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 13 Sep 2012 03:24:26 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ ZOJ2301(HDU1199) Color the Ball（离散化）]]></title>
      <description><![CDATA[ 		题意是说，有从 1 开始递增依次编号的很多球，开始他们都是黑色的，现在依次给出 n 个操作（ai，bi，ci） ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22977.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22977.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 13 Sep 2012 02:50:21 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 2153 Rank List map的应用]]></title>
      <description><![CDATA[ 		题意：一个人有一些考试，每次得到一个分数，问经过i次考试后总分排名第几。
思路：map的应用，一一对应 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22976.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22976.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 13 Sep 2012 02:27:24 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 4125 2011福州现场赛E题 KMP+笛卡尔树]]></title>
      <description><![CDATA[ 		题意就不描述了。 主要说一下我的构造第一个串的过程
 
对给出的序列，比如5 1 3 2 7 8 4 6
 
给每个 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22975.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22975.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 09:08:24 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ HDU 4282 A very hard mathematic problem（12天津网络赛-数学）]]></title>
      <description><![CDATA[ 		题目链接：Click here~~
题意：
给你一个式子x^z + y^z + x*y*z = k，k 为给定的某个int 范围内的数字。 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22974.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22974.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 08:53:58 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ hdu 3395]]></title>
      <description><![CDATA[ 		直接按题意建图。KM算法求解。
cpp 
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt;cstring&amp;gt; 
using namespace std;  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22973.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22973.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 07:55:56 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 2282]]></title>
      <description><![CDATA[ 		将题目的问题转化成 以每个盒子里多余的巧克力，到空盒子的最优匹配问题。
 
下面是AC代码：
cpp
# ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22972.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22972.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 07:52:12 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 2426]]></title>
      <description><![CDATA[ 		
二分图的最优匹配。用KM算法解决。题目要求找到最大的权值。同时要n个人都要匹配到。注意细节。下面是A ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22971.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22971.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 05:45:04 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 4274 Spy&#039;s Work（12年长春 树形DP）]]></title>
      <description><![CDATA[ 		题目：给出一棵树，给出一些子树的权值关系，问是否矛盾 
初始对于所有结点以及子树的下限为1，上限可能 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22970.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22970.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 05:40:08 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 1698 Just a Hook]]></title>
      <description><![CDATA[ 		思路：线段树操作区域覆盖
每个线段树的结点，存储该结点所代表区间的金属c，如果该区间全为同样的材料， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22969.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22969.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 05:29:48 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 2853]]></title>
      <description><![CDATA[ 		二分图的最优匹配。因为题目上的节点最多只有50个。所以先对所有权值*100，把原来各个匹配关系的权值+1， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22968.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22968.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 05:08:46 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[三张图片拼接成圆角框]]></title>
      <description><![CDATA[ 		圆角框在WEB界面经常会用到的元素，正因为如此，人们也研究出了很多实现圆角框的解决方案。每种方案都有各 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22967.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22967.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 03:37:51 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ hdu 1853 | hdu 3488 | hdu3435]]></title>
      <description><![CDATA[ 		二分图的最优匹配。求最小费用流。要求所有点匹配下的最小费用，直接套用KM算法的即可。。下面是 1853 AC ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22966.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22966.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 02:01:09 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[实现不规则窗体------基于MFC based DLG]]></title>
      <description><![CDATA[ 		实现界面如下所示：（文末有源码下载地址，初写技术博客，写的不好还请大家多多批评指正） 实现过程：1、 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22965.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22965.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 01:53:07 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu Leftmost Digit]]></title>
      <description><![CDATA[ 		思路：刚开始做，发现很纠结！！后来，看到了一个人的分析，是这样转换的m=n^n;两边同取对数，得到，log1 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22964.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22964.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 01:27:01 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 2932 扫描线思想]]></title>
      <description><![CDATA[ 		这个题确实太神奇了大意就是给出了n个互不相交的圆。 各个圆之间有可能一个完全包含了另一个。这里包含就 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22963.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22963.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 01:20:20 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++ 中有用的“计时器”]]></title>
      <description><![CDATA[ 		头文件： #include&amp;lt;windows.h&amp;gt;
 
 DWORD dwStartTime = GetTickCount(); // 用dwStartTime记录起始时间 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/22962.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/22962.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 00:53:23 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 4281 Judges&#039; response（12年天津 MTSP问题）]]></title>
      <description><![CDATA[ 		题目：给出N个人，其中0号是裁判的位置，剩下有N-1的人提问，裁判需要去回答问题，每个人有一个val，每个 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23061.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23061.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 00:51:43 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[438. The Glorious Karlutka River =)]]></title>
      <description><![CDATA[ 		题目大意：河中有一些漂浮物，每个漂浮物有一个容量。求m个人过河的最短时间。题目思路：经典题目,加上时 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23060.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23060.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 00:49:54 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 2255]]></title>
      <description><![CDATA[ 		
二分图的最优匹配（最大权值）。用KM算法解决。纯模板。下面是AC代码：
cpp
#include&amp;lt;cstdio&amp;gt; 
#i ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23059.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23059.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 12 Sep 2012 00:44:28 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 2778 AC自动机]]></title>
      <description><![CDATA[ 		这题还是挺经典的首先的话，是建立自动机的过程。其实就是一个状态的转移，看一个字典树中的某子串加上一 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23058.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23058.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 09:17:36 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ hdu bignumber]]></title>
      <description><![CDATA[ 		数学真是源远流长啊！！现在又有斯特林数log10(n!)=1.0/2*log10(2*pi*n)+n*log10(n/e)现在我对数学的崇拜 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23057.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23057.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 09:13:08 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu3980 Paint Chain------sg 环--链 一排石子分成若干堆]]></title>
      <description><![CDATA[ 		Paint Chain
Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23056.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23056.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 08:26:13 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Codeforces Round #137 (Div. 2)]]></title>
      <description><![CDATA[ 		不是很难的一场~~~A. Shooshuns and Sequence
随便YY下吧，首先必须从k个之后，都是相同的，否则不管怎么 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23055.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23055.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 08:10:06 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 1179]]></title>
      <description><![CDATA[ 		
裸题。。二分图的最大匹配。、下面是AC代码：
cpp
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt;cstring&amp;gt; 
using  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23054.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23054.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 07:23:41 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 3367 Pseudoforest （伪森林）]]></title>
      <description><![CDATA[ 		
题目：
Problem Description
In graph theory, a pseudoforest is an undirected graph in which eve ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23053.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23053.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 06:57:12 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 1068]]></title>
      <description><![CDATA[ 		
求最大独立集 = n （顶点数）- 最大匹配/2(这里的最大匹配因为是无向图，所以除2)
(转)本题中的A集合为 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23052.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23052.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 06:03:31 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 1151]]></title>
      <description><![CDATA[ 		二分图最小路径覆盖=点的个数-最大匹配。。下面 是 AC代码：
cpp 
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt;cstr ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23051.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23051.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 05:21:11 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj 2822 &amp;amp;amp; hdu 4280 &amp;amp;lt;平面图网络流&amp;amp;gt;]]></title>
      <description><![CDATA[ 		对于10^5个点10^6条边的网络流，一般做法无法高效解决，如果所有边都是双向边且网络能构成一个平面图，则 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23050.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23050.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 05:14:31 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 3938 Portal（离线+Kruskal+并查集）]]></title>
      <description><![CDATA[ 		
题目：
Problem Description
ZLGG found a magic theory that the bigger banana the bigger banana  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23049.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23049.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 03:07:25 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 4284 Travel(12年天津 状态DP)]]></title>
      <description><![CDATA[ 		题目：给出一些城市，从1出发，旅游一圈回到1，由于花费可能不够，所以选择一些城市打工，打工之前需要花 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23048.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23048.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 02:45:44 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++中两个类互相包含的策略]]></title>
      <description><![CDATA[ 		C++中两个类互相包含的策略
一，问题描述
        A类包含B类的实例，而B类也包含A类的实例
 
二，求 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23047.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23047.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 02:36:46 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ACM在命令行以LED样式显示输入的数字]]></title>
      <description><![CDATA[ 		昨天，一个同学和我说了一道ACM题目，说很有趣，于是乎我就听了他给我介绍了题目的要求：每行输入两个数如 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23046.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23046.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 02:35:07 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[开源项目之在线网页截图工具 IECapt]]></title>
      <description><![CDATA[ 		       这个项目是win32程序，就一个目标文件。
        class CEventSink :public CComObjectRootEx &amp;lt;C ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23045.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23045.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 02:25:24 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[CCS工程中cmd文件的编写]]></title>
      <description><![CDATA[ 		Section目标文件中最小单位称为块，一个块就是最终在存储器映象中占据连续空间的一段代码或数据。1、COFF ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23044.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23044.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 01:58:20 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[打印出所有可能的括号组合]]></title>
      <description><![CDATA[ 		以下为递归方法实现
cpp
#include &amp;lt;vector&amp;gt; 
#include &amp;lt;iostream&amp;gt; 
 
#define N 3 
 
void prin ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23043.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23043.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 01:53:30 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 4279 Number]]></title>
      <description><![CDATA[ 		1思路：数学题+找规律
2分析：
          1这一题的数据范围很大（1---z^63-1），而给定的时间肯定才1s ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23042.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23042.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 01:46:44 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ HDU 1215 七夕节]]></title>
      <description><![CDATA[ 		思路：简单的筛选cpp 
#include&amp;lt;stdio.h&amp;gt; 
#define N 500005 
int sumN; 
void is_prime()//采用 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23041.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23041.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 01:46:02 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[刨根问底系列之C++ const 挖掘]]></title>
      <description><![CDATA[ 		一、 const的作用：     1、限定const指定的值的修改          ex1.1：          const int a = 2;       ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23040.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23040.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 01:39:17 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 1083]]></title>
      <description><![CDATA[ 		二分图的最大匹配。。直接用套用匈牙利算法即可。下面是AC代码：
cpp 
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt; ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23039.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23039.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 01:32:23 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 4286 Data Handler（12天津网络赛-模拟）]]></title>
      <description><![CDATA[ 		题意：
给一列数字，一个左指针 L 和一个右指针 R。
然后有7种操作。
最后输出操作完的结果。
比赛时 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23038.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23038.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 01:27:56 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu4279 Number-------天津网络赛 打表找规律]]></title>
      <description><![CDATA[ 		Number
Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23037.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23037.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 01:07:16 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[不使用man 3 printf的函数，实现一个简单的printf函数]]></title>
      <description><![CDATA[ 		题目：不使用man printf中的函数，实现一个简易的输出函数myprintf。
函数声明：int myprintf(const cha ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23036.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23036.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 01:00:44 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 1286 找新朋友]]></title>
      <description><![CDATA[ 		思路：用欧拉函数找与N互质数的数量cpp
#include&amp;lt;iostream&amp;gt; 
#include&amp;lt;cstdio&amp;gt; 
using namespace st ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23035.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23035.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 11 Sep 2012 00:56:21 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu4282 A very hard mathematic problem-----天津网络赛]]></title>
      <description><![CDATA[ 		A very hard mathematic problem
Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/3276 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23034.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23034.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 10 Sep 2012 09:20:06 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ hdu 4282 A very hard mathematic problem]]></title>
      <description><![CDATA[ 		 
1思路：   枚举z的范围(2-31)，然后枚举x的值1-&amp;gt;pow(x,z)&amp;gt;=k/2，最后二分查找y的值即可。
2分析：  1 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23033.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23033.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 10 Sep 2012 09:16:09 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[UVA_10716 - Evil Straw Warts Live-------水题（模拟）]]></title>
      <description><![CDATA[ 		cpp 
#include&amp;lt;cstdlib&amp;gt; 
#include&amp;lt;iostream&amp;gt; 
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt;cmath&amp;gt; 
#include&amp;lt;set ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23032.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23032.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 10 Sep 2012 09:08:13 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU-4287-Intelligent IME]]></title>
      <description><![CDATA[ 		HDU-4287-Intelligent IME
 
http://acm.hdu.edu.cn/showproblem.php?pid=4287
 
开始用字典树+深搜， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23031.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23031.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 10 Sep 2012 09:03:53 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++中类的学习]]></title>
      <description><![CDATA[ 		 我们先来了解一下什么是类？
 类是对逻辑上相关的函数与数据的封装
 下面是我对类的总结：认识一个类， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23030.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23030.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 10 Sep 2012 08:40:36 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Hdu 4281 Judges&#039; response (DP_背包|TSP)]]></title>
      <description><![CDATA[ 		题目大意:给定n个地点的坐标和每个地点的权值，即一张图n个点，点有点权边有边权。现在裁判在点1，需要分 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23029.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23029.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 10 Sep 2012 08:20:37 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 1811 Rank of Tetris(拓扑排序+并查集)]]></title>
      <description><![CDATA[ 		题目：
Problem Description
自从Lele开发了Rating系统，他的Tetris事业更是如虎添翼，不久他遍把这个游 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23028.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23028.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 10 Sep 2012 07:01:15 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj 1094 Sorting It All Out(拓扑排序)]]></title>
      <description><![CDATA[ 		题目：
Sorting It All Out
Time Limit: 1000MS   Memory Limit: 10000K
Total Submissions: 21532    ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23027.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23027.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 10 Sep 2012 05:53:41 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU1176]]></title>
      <description><![CDATA[ 		
java 
package DP; 
 
import java.util.*; 
 
public class HDU1176 { 
    // arrij表示 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23026.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23026.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 10 Sep 2012 05:09:15 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ HDU2151]]></title>
      <description><![CDATA[ 		java 
 
import java.util.*; 
 
public class HDU2151 { 
 
    public static void main(Strin ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23025.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23025.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 10 Sep 2012 05:06:53 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU1087]]></title>
      <description><![CDATA[ 		java 
package DP; 
 
import java.util.*; 
 
//状态转移方程 bi=max(bi, bj+ai); 
pub ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23024.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23024.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 10 Sep 2012 03:56:02 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++与C#对比学习:面向对象,class类(一)]]></title>
      <description><![CDATA[ 		面向对象的小故事   
      面向对象程序语言中最重要的概念无疑是class,所谓一切皆对象.(不过要是老天天 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23023.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23023.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 10 Sep 2012 03:30:48 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++ Primer学习笔记 - 第三章]]></title>
      <description><![CDATA[ 		使用using 声明cpp
#include &amp;lt;iostream&amp;gt; 
#include &amp;lt;string&amp;gt; 
 
using std::cin; 
using std::cou ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23022.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23022.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 10 Sep 2012 01:12:17 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++ Primer学习笔记 - 第一章]]></title>
      <description><![CDATA[ 		cpp
#include &amp;lt;iostream&amp;gt; 
 
int main() 
{ 
    std::cout &amp;lt;&amp;lt; &amp;quot;Enter two numbers: &amp;quot; &amp;lt;&amp;lt; std::en ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23021.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23021.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 10 Sep 2012 01:08:40 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++11新特性：Range-based for loops]]></title>
      <description><![CDATA[ 		很多语言都有Range-based for loops这个功能，现在C++终于知道把这个重要功能加进语法中了。这个功能实在 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23020.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23020.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 10 Sep 2012 01:00:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++修改入口函数名Main的方法]]></title>
      <description><![CDATA[ 		方法1:
cpp 
// 通过下面这句话将入口函数改成fn. 
#pragma comment(linker, &amp;quot;/entry:fn&amp;quot;) 
#inclu ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23017.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23017.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 08 Sep 2012 23:51:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[微软等数据结构与算法面试100题 第二十一题]]></title>
      <description><![CDATA[ 		第二十一题
题目：
输入两个整数n 和m，从数列1，2，3.......n 中随意取几个数,
使其和等于m ,要求将其 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23019.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23019.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 08 Sep 2012 23:45:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C/C++和指针深度解析---指针与数组]]></title>
      <description><![CDATA[ 		一，引例子
二维数组可以使用指向数组的指针代替，而指针数组才可以用指向指针的指针代替。
html vie ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23018.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23018.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 08 Sep 2012 23:28:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu2999 Stone Game, Why are you always there?---sg 一排石子分成若干堆]]></title>
      <description><![CDATA[ 		 Stone Game, Why are you always there?
Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23015.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23015.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 08 Sep 2012 07:13:31 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Windows共享内存 C++及C#实现]]></title>
      <description><![CDATA[ 		FileMapping用于将存在于磁盘的文件放进一个进程的虚拟地址空间，并在该进程的虚拟地址空间中产生一个区域 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23014.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23014.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 08 Sep 2012 05:45:09 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++新发现]]></title>
      <description><![CDATA[ 		1. 类1中引用了类2中定义的某个枚举、结构体或者他们的类型，那么，也会去掉类2的构造函数来造出这些个类 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23013.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23013.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 08 Sep 2012 05:39:01 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 1379 Run Away(基础模拟退火)]]></title>
      <description><![CDATA[ 		题目：找出一点，距离所有所有点的最短距离最大
 
http://poj.org/problem?id=1379
 
 
随机化步长， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23012.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23012.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 08 Sep 2012 05:15:38 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[c/c++字节对齐]]></title>
      <description><![CDATA[ 		在 相同的对齐方式下 ，结构体内部数据 定义的顺序不同 ，结构体整体占据内存空间也 不同 ，如下：
设结 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23111.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23111.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 08 Sep 2012 05:08:33 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 1106 排序]]></title>
      <description><![CDATA[ 		Problem Description
输入一行数字，如果我们把这行数字中的&amp;amp;lsquo;5&amp;amp;rsquo;都看成空格，那么就得到一行 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23110.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23110.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 08 Sep 2012 05:06:17 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C/C++ struct位结构（位域）]]></title>
      <description><![CDATA[ 		从问题开始#include
void main()
{
union
{
struct
{
unsigned short s1:3;
unsigned short s2:3 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23109.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23109.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 08 Sep 2012 02:21:59 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu2873 Bomb Game-----sg]]></title>
      <description><![CDATA[ 		Bomb Game
Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
To ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23108.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23108.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 08 Sep 2012 02:17:16 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ Poj 1170 Shopping Offers (DP_状态压缩DP)]]></title>
      <description><![CDATA[ 		题目大意：给定一个订单n种商品，每种商品有个初始价格pri，初始数量numi，再给定m种组合，这些组合会得到 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23107.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23107.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 07 Sep 2012 08:58:38 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Poj 2411 Mondriaan&#039;s Dream (DP_状态压缩DP)]]></title>
      <description><![CDATA[ 		题目大意: 给定一个n*m的方格矩形，求用1*2的小矩形完全覆盖的方案数，n &amp;lt;= 11,m &amp;lt;= 11.解题思路： 挺经典 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23106.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23106.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 07 Sep 2012 08:52:56 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU1850 Being a Good Boy in Spring Festivaly]]></title>
      <description><![CDATA[ 		Nim博弈
题意：有m堆牌，两个人先后取某堆中的任意（不少于一）张牌，最后取完者胜；问先手取胜第一次取 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23105.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23105.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 07 Sep 2012 07:43:17 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ hdu 1569 方格取数]]></title>
      <description><![CDATA[ 		题目大意：求在n*m的棋盘中选出两两不相邻的数，使得和最大。题目思路：按国际象棋黑白染色,源点到黑点容 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23104.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23104.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 07 Sep 2012 07:33:54 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[引用类型参数的初始化及可能出现的问题]]></title>
      <description><![CDATA[ 		引用转载请注明出处，谢谢！使用引用类型进行返回值的传递经常可以看到，其优点非常明显，如果引用的是对 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23103.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23103.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 07 Sep 2012 07:25:28 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[归并排序 例题即模版 XMU1328 hdu3743]]></title>
      <description><![CDATA[ 		cpp 
#include &amp;lt;stdio.h&amp;gt;   
#include &amp;lt;stdlib.h&amp;gt;   
#define MAXN 1000100   
int inputMAXN =  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23102.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23102.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 07 Sep 2012 07:06:04 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++ Primer 学习笔记 - 第一章]]></title>
      <description><![CDATA[ 		cpp
#include &amp;lt;iostream&amp;gt; 
 
int main() 
{ 
    std::cout &amp;lt;&amp;lt; &amp;quot;Enter two numbers: &amp;quot; &amp;lt;&amp;lt; std::en ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23101.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23101.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 07 Sep 2012 05:55:22 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 1064 Cable master 浮点数二分]]></title>
      <description><![CDATA[ 		题意：有一些棍子，这些棍子的长度已知，现在要将这些棍子分成m段，问分的棍子最长是多少。
思路：二分枚 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23100.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23100.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 07 Sep 2012 03:04:08 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[非静态成员函数做窗口过程（非映射表实现），成员函数做消息映射]]></title>
      <description><![CDATA[ 		之前看mfc的原理是做类指针对窗口句柄的映射表；实现了几个版本，总觉得查找映射表是件很浪费不优雅的事情 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23099.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23099.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 06 Sep 2012 09:18:02 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj1022:Packing Unit 4D Cubes四维魔方的题意和题解]]></title>
      <description><![CDATA[ 		囧，题意看起来 很复杂，故几乎没什么人提交，其实只要看懂了题目的意思再简单不过了，，，这不，因为英语 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23098.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23098.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 06 Sep 2012 06:20:57 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 4311]]></title>
      <description><![CDATA[ 		题意：
给你n个点。选择一个点，是其他点到这个点的Manhattan 距离最小
思路：
平面上两点间的 Manhat ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23097.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23097.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 06 Sep 2012 06:12:15 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[NYOJ 171 聪明的kk]]></title>
      <description><![CDATA[ 		点击打开链接NYOJ 171
1题目：
                                                                    ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23096.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23096.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 06 Sep 2012 06:07:06 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[解读Blueprint CSS framework]]></title>
      <description><![CDATA[ 		&amp;lt;link rel=&amp;quot;stylesheet&amp;quot; href=&amp;quot;http://www.cnblogs.com/blueprint/screen.css&amp;quot; type=&amp;quot;text/css&amp;quot; media=&amp;quot;s ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23095.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23095.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 06 Sep 2012 05:36:54 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[SPOJ HACKING]]></title>
      <description><![CDATA[ 		题意:给出一个长为 n 的,由字母表中前 k 个小写字母组成的字符串 s.求一个长度为m的字符串,要求该串也只能 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23094.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23094.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 06 Sep 2012 05:24:25 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++关键字static的用法]]></title>
      <description><![CDATA[ 		1、cpp文件中的全局静态变量全局内的声明：static int a=0;这样的静态全局变量就只能被该cpp文件所用，不 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23093.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23093.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 06 Sep 2012 03:50:01 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 3415 Common Substrings(后缀数组+单调栈)]]></title>
      <description><![CDATA[ 		题目：求出长度不小于k的公共子串个数 
继续论文上的题目。计算A的某个后缀与B的某个后缀的最长公共前缀 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23092.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23092.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 06 Sep 2012 03:10:25 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU1874　畅通工程续]]></title>
      <description><![CDATA[ 		简短的最短路问题  Dijkstra算法求解cpp
#include&amp;lt;iostream&amp;gt; 
#include&amp;lt;cstdio&amp;gt; 
using namespace s ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23091.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23091.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 06 Sep 2012 03:05:11 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 3973 AC&#039;s String]]></title>
      <description><![CDATA[ 		本题使用字符串的Hash来解决。将一个字符串看成是一个P进制的数字，那么可以知道每一个字符串都可以被唯一 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23090.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23090.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 06 Sep 2012 02:59:09 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[c++ 指针point 和引用reference的区别]]></title>
      <description><![CDATA[ 		1.reference一定得代表某个对象，即reference必须有初值；而point没有这种要求，因此它可以有null pointe ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23089.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23089.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 06 Sep 2012 02:52:58 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Codeforces Beta Round #7, problem: (D) Palindrome Degree]]></title>
      <description><![CDATA[ 		cpp 
#include&amp;lt;iostream&amp;gt; 
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt;cstdlib&amp;gt; 
#include&amp;lt;cstring&amp;gt; 
__int64 dp ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23088.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23088.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 06 Sep 2012 02:44:05 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Myacm Triangles hoj，poj，uva 计算几何]]></title>
      <description><![CDATA[ 		cpp
/*暴力枚举。
判断点是否在三角形内，用叉积求面积。
*/ 
#include &amp;lt;stdio.h&amp;gt; 
#include &amp;lt;cma ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23087.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23087.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 06 Sep 2012 02:43:22 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Uniform Generator数学题]]></title>
      <description><![CDATA[ 		cpp
/*这种题写过两次。第一次周赛的第一道就是他。就是给两个数，a,b.amodb的结果，再mod b,如果所有 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23086.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23086.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 06 Sep 2012 02:32:22 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[FZU 1901]]></title>
      <description><![CDATA[ 		简单KMPcpp
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt;cstring&amp;gt; 
#include&amp;lt;vector&amp;gt; 
#include&amp;lt;algorithm&amp;gt; 
usin ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23085.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23085.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 06 Sep 2012 01:31:53 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[NYOJ 214 单调递增子序列]]></title>
      <description><![CDATA[ 		描述
    给定一整型数列{a1,a2...,an}（0&amp;lt;n&amp;lt;=100000），找出单调递增最长子序列，并求出其长度。
     ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23084.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23084.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 06 Sep 2012 00:57:05 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 4310 Hero]]></title>
      <description><![CDATA[ 		Problem A
Time Limit : 6000/3000ms (Java/Other) Memory Limit : 65536/65536K (Java/Other)Total Sub ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23083.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23083.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 05 Sep 2012 07:22:59 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[高斯消元专题]]></title>
      <description><![CDATA[ 		由于老师的讲课，我又重拾高斯消元，做了一天的高斯，感觉老师讲得很好，模板也不错，我懒得自己写，就把 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23082.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23082.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 05 Sep 2012 07:06:22 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[线段树POJ 2374 Fence Obstacle Course]]></title>
      <description><![CDATA[ 		我们可以开一个一维数组w，数组下标就是区间的端点值，cow刚开始在ws处。碰到一个区间后，我们看这个 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23081.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23081.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 05 Sep 2012 02:13:44 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[XP下，麦克风加强]]></title>
      <description><![CDATA[ 		cpp
bool CMicrophoneEnhance::SetEnhance(bool enhance, DWORD type) 
{ 
&amp;lt;span style=&amp;quot;white-spac ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23080.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23080.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Wed, 05 Sep 2012 01:27:34 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Fukuoka 2011 F - City Merger &amp;amp;lt;路径压缩,位运算,AC自动机&amp;amp;gt;]]></title>
      <description><![CDATA[ 		本题求用最短的长度字符串包含所给子串...由于存在多串匹配的问题...容易联想到AC自动机...
       最多 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23079.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23079.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 04 Sep 2012 08:49:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[mfc实现播放器功能，双击全屏，再双击还原]]></title>
      <description><![CDATA[ 		视频播放器的制作，视频流在静态控件上显示，类似迅雷看看双击全屏操作的实现
 
在主窗口的 .h 文件中 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23078.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23078.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 04 Sep 2012 08:34:45 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[以BCD(16进制)码存储的Char数据以Int型表示]]></title>
      <description><![CDATA[ 		char型数据里面的数据是以16进制数存储的，每个char型数据的可能值是从0x00~0xff(表示为2进制范围是从000 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23077.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23077.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 04 Sep 2012 08:07:55 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu 1598]]></title>
      <description><![CDATA[ 		
可以用并查集，也可以用二分+单元最短距离做。思路都差不多。都是枚举上下界。先将速度排序。然后枚举上 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23076.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23076.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 04 Sep 2012 08:02:50 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[二叉树的各种操作复习]]></title>
      <description><![CDATA[ 		cpp 
/*二叉树的各种操作复习*/ 
#include &amp;lt;stdio.h&amp;gt; 
 
#define BACK_ODER   -1 
#define IN_ODE ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23075.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23075.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 04 Sep 2012 07:56:11 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 3696 The Luckiest number（08合肥 数论）]]></title>
      <description><![CDATA[ 		题目：给出一个数n，找出他的一个倍数，而且这个数每一位都是8，找到最小的那个的位数，否则输出0. 
其实 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23074.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23074.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 04 Sep 2012 07:48:23 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ POJ 1084 Square DestroyerDancing Links重复覆盖]]></title>
      <description><![CDATA[ 		Square Destroyer
Time Limit: 1000MS   Memory Limit: 10000K
Total Submissions: 2695   Accepted: 1 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23073.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23073.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 04 Sep 2012 07:05:02 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj 3255 Roadblocks 次短路]]></title>
      <description><![CDATA[ 		  这个题是求次短路。有个不错的解法，是根据一个结论，替换调最短路里面的一条边肯定能得到次短路。
   ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23072.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23072.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 04 Sep 2012 06:36:41 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C/c++中的--&amp;amp;gt;运算符]]></title>
      <description><![CDATA[ 		c/c++中以下代码是合法的：#include &amp;lt;stdio.h&amp;gt;
int main()
{
     int x = 10;
     while( x --&amp;gt; 0  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23071.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23071.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 04 Sep 2012 06:30:28 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 3349 Snowflake Snow Snowflakes]]></title>
      <description><![CDATA[ 		上次在BFS的时候需要hash判重，但是很少接触hash的用法，其实还是和数据结构讲得一样，就是用一个公式起到 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23070.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23070.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 04 Sep 2012 05:59:41 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[HDU 3498 whosyourdaddyDancing Links重复覆盖]]></title>
      <description><![CDATA[ 		有n个单位的敌人，对某个敌人进行攻击时该敌人以及与其直接相邻的敌人都会被消灭。问消灭所有敌人所需的最 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23069.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23069.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 04 Sep 2012 03:13:28 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj 2449 k短路模板]]></title>
      <description><![CDATA[ 		cpp
#include &amp;lt;iostream&amp;gt; 
#include &amp;lt;stdio.h&amp;gt; 
#include &amp;lt;cstring&amp;gt; 
#include &amp;lt;queue&amp;gt; 
#include ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23068.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23068.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 04 Sep 2012 02:25:29 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[MFC中控件的大小和位置自定义代码]]></title>
      <description><![CDATA[ 		cpp 
CRect   rect;  
rect.SetRect(NULL,NULL,700,100);  
//MapDialogRect(rect);  加上就全屏了  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23067.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23067.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 04 Sep 2012 02:20:24 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[输入一个英文句子，翻转句子中单词的顺序，单词内字符顺序不变]]></title>
      <description><![CDATA[ 		cpp&amp;lt;p&amp;gt;题目：输入一个英文句子，翻转句子中单词的顺序，但单词内字符的顺序不变。句子中单词以空格符隔 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23066.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23066.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Tue, 04 Sep 2012 02:06:58 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 3272 Monthly Expense 二分]]></title>
      <description><![CDATA[ 		题意：给你n个数，让分成m组，每组必须是连续的一些数，求每组的和的最大值最小。
思路：二分枚举答案。 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23065.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23065.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 08:51:48 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[基础备忘：派生类直接访问基类的私有成员]]></title>
      <description><![CDATA[ 		派生类不能直接访问基类的私有成员，若要访问必须使用基类的接口，即通过其成员函数。实现方法有如下两种 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23064.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23064.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 08:11:13 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu1021 Fibonacci Again]]></title>
      <description><![CDATA[ 		看题目请点这里题意：F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n&amp;gt;=2)，若F（i）%3=0，输出yes，否则 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23063.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23063.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 06:48:31 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[递归思想实现全排列]]></title>
      <description><![CDATA[ 		cpp 
#include &amp;lt;stdio.h&amp;gt; 
 
int Swap(char *a,char *b) 
{ 
    char c; 
    c = *a; 
    *a ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23062.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23062.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 06:41:06 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Help the Hurricane Victims 删边法的次短路]]></title>
      <description><![CDATA[ 		cpp 
/*之前用两种方法写过次短。分别是两次的spfa和二维的dij。其中应该是以两次的spfa的效率最高。二 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23161.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23161.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 06:23:32 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[GCPC2011 - A Faculty Dividing Powers]]></title>
      <description><![CDATA[ 		题意是说给出n , k 求出最大的 i 使得 n! % k^i == 0 ...
     假设最简单的情况...k是质数...要求 n! = ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23160.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23160.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 06:03:06 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj Roadblocks 次短路（数据较大）]]></title>
      <description><![CDATA[ 		cpp
/*这种思路是在网上借鉴的。很好。速度也非常快。自己实现了一遍。在poj上181MS。
主要是分别一起 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23159.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23159.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 05:28:47 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[zoj3556 How Many Sets I-------容斥]]></title>
      <description><![CDATA[ 		How Many Sets I
Time Limit: 2 Seconds      Memory Limit: 65536 KB
Give a set S, |S| = n, then ho ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23158.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23158.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 05:24:30 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ1328 Radar Installation贪心]]></title>
      <description><![CDATA[ 		题意：有一条海岸线，在海岸线上方是大海，海中有一些岛屿，这些岛的位置已知，海岸线上有雷达，雷达的覆 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23157.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23157.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 03:38:39 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu3275 Light很好很好的线段树收获丰富]]></title>
      <description><![CDATA[ 		Light
Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23156.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23156.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 02:58:11 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++中实现回调机制的几种方式]]></title>
      <description><![CDATA[ 		（1）Callback方式
Callback的本质是设置一个函数指针进去，然后在需要需要触发某个事件时调用该方法, 比 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23155.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23155.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 02:37:20 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[hdu2461 Rectangles-----容斥]]></title>
      <description><![CDATA[ 		Rectangles
Time Limit: 5000/4000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
T ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23154.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23154.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 02:31:48 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[顺序存储的线性表]]></title>
      <description><![CDATA[ 		cpp 
/*
 * 顺序存储的线性表
 */ 
#include &amp;lt;stdio.h&amp;gt; 
 
#define OK 1 
#define ERR 0 
 
# ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23153.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23153.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 01:56:53 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++中模块(Dll)对外暴露接口的几种方式]]></title>
      <description><![CDATA[ 		总结下C++中模块(Dll)对外暴露接口的方式：(1)导出API函数的方式
这种方式是Windows中调用DLL接口的最基 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23152.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23152.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 01:17:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj 3093 Margaritas on the River Walk]]></title>
      <description><![CDATA[ 		这是一个动态规划题，据说是背包问题的变形。我动态规划做得很少，解法一直按照算法导论的思想分解重叠子 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23151.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23151.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 01:12:57 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++复习笔记---浅谈拷贝构造函数和赋值构造函数]]></title>
      <description><![CDATA[ 		1.拷贝构造函数的形式
对于类X，如果它的函数形式如下
a) X&amp;amp;
b) const X&amp;amp;
c) volatile X&amp;amp;
d) const  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23150.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23150.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 01:10:09 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[小议c++之回调]]></title>
      <description><![CDATA[ 		 最近在做一个军团系统的资料片开发，因为策划提出了很多遍历某一军团当前所有在线玩家的操作(例如发公告 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23149.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23149.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 01:07:04 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj 2823 Sliding Window单调队列]]></title>
      <description><![CDATA[ 		这道题的意思是给定一个长N的整数序列，用一个大小为K的窗口从头开始覆盖，问第1-第N-K次窗口里面最大的数 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23148.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23148.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Mon, 03 Sep 2012 00:44:10 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[C++类的大小]]></title>
      <description><![CDATA[ 		一个空类class A{};的大小为什么是1，因为如果不是1，当定义这个类的对象数组时候A objects5; objects ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23144.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23144.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sun, 02 Sep 2012 00:20:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[消息队列学习小结]]></title>
      <description><![CDATA[ 		cpp
//  ipcs -q -i 0 
//  Semaphore Arrays 
//  Shared Memory Segments 
//  Messages Queues  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23139.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23139.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 23:51:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[basler pilot系列相机 MFC opencv]]></title>
      <description><![CDATA[ 		采用MFC+ opencv 对basler pilot系列相机，通过千兆以太网接口实现图像数据获取，运行示例程序能够正常获 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23147.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23147.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 23:50:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj 1430 Binary Stirling Numbers]]></title>
      <description><![CDATA[ 		第二类Stirling数是把包含n个元素的集合划分为正好k个非空子集的方法的数目。
递推公式为：
S(n,k) = 0 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23146.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23146.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 23:48:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 1743 Musical Theme（后缀数组求不可重叠最长重复子串）]]></title>
      <description><![CDATA[ 		题目：给出一些音符，求出最长的重复出现的旋转长度。 
从题目中的意思可以知道，只要满足相邻的差相等便 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23140.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23140.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 23:42:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[线性表之数组---C++语言描述]]></title>
      <description><![CDATA[ 		感觉用C++中的构造函数、析构函数等类的特点来描述一些数据结构更加易读，更加合理，便捷。但有一个问题， ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23145.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23145.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 23:34:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ CodeForces Round #136(220B) - Little Elephant and Array]]></title>
      <description><![CDATA[ 		本题的关键之处在于发现10^5中~~最多小于450个符合要求的x.这种情况是1+2+3+4+....+n&amp;lt;=100000....得n&amp;lt;450 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23143.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23143.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 23:04:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 2992 Divisors]]></title>
      <description><![CDATA[ 		    这种题目，纯粹是折磨人的。那么容易TLE，昨天做了一个上午都没做出来，今天算是改对了，杨大哥说把素 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23142.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23142.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 22:56:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[poj1721 CARDS]]></title>
      <description><![CDATA[ 		CARDS
Time Limit: 1000MS   Memory Limit: 10000K
Total Submissions: 1030   Accepted: 542
Descrip ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23141.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23141.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 22:48:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 1830（位运算+双向DFS）]]></title>
      <description><![CDATA[ 		此题也可用GE做，可是我不会矩阵乘法&amp;amp;hellip;&amp;amp;hellip;delphi 
Program P1830; 
const 
   maxn=28;  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23138.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23138.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 03:31:48 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[出道题大家做做，C++的（含答案）]]></title>
      <description><![CDATA[ 		1.      Reverse the words in a given English sentence (string) in C or C++ without requiring a sep ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23137.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23137.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 02:46:35 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[CodeForces Round #136(220B) - Little Elephant and Array]]></title>
      <description><![CDATA[ 		  本题的关键之处在于发现10^5中~~最多小于450个符合要求的x.这种情况是1+2+3+4+....+n&amp;lt;=100000....得n&amp;lt;4 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23136.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23136.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 02:43:46 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[CodeForces Round #123 (195C) - Try and Catch]]></title>
      <description><![CDATA[ 		   题意有些难捉摸~~看了蛮久才懂...这题我是用各种STL水过的了~~stack,map+stack...本以为效率会很低~~但 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23133.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23133.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 02:27:20 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ CodeForces Round #123 (195D) - Analyzing Polylin]]></title>
      <description><![CDATA[ 		这道题一开始题目看错了...理解了好久才知道题目意思..呃~~其实就是说这些折线叠加..会产生多少拐点...
 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23134.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23134.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 02:18:10 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[CodeForces Round #120 (190D) - Non-Secret Cypher]]></title>
      <description><![CDATA[ 		本题我用了一个类似单调队列的东西...
     将数列中每个点的位置和a记录..并优先级按先a再位置排序~~这 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23132.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23132.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 02:08:12 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[CodeForces Round #119 (187B) - AlgoRace]]></title>
      <description><![CDATA[ 		 这道题我想啦好久~~只想出了dp6060601000这种完全没效率的DP(更新的时候也要扫描60^3的空间...s ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23131.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23131.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 01:59:15 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[CodeForces Round #118 - Mushroom Scientists]]></title>
      <description><![CDATA[ 		   这题A得很神奇...俺只是做了个猜测..写了如下无比猥琐丑陋的代码..居然真给AC了...
     我就是一位一 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23129.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23129.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 01:32:23 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[CodeForces Round #118 (185A) - Plant]]></title>
      <description><![CDATA[ 		这次比赛的时间是23:30开始...囧...写了一道A题就回去睡觉了..这场比赛有三道题A的人很多..本题就是一个很 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23128.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23128.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 01:30:57 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ CodeForces Round #119 (187A) - Permutations]]></title>
      <description><![CDATA[ 		  这题突破点或者说关键之处就在第二列最后一个数在第一列中的位置...
      设第二列最后一个数为x...设 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23130.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23130.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 01:29:41 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[CodeForces Round #116 (180E) - Cubes]]></title>
      <description><![CDATA[ 		第一次做CF的contest...昨天的Easy题目刷了5道回去睡了..今天的比赛开始还是很顺利的..唰唰两道大水题很快 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23127.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23127.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 01:24:31 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[CodeForces Round #134(217B) - Blackboard Fibonacci]]></title>
      <description><![CDATA[ 		本题的关键是抓住在过程中T,B两数的关系...如果当前的操作是&amp;amp;#39;T&amp;amp;#39;...那么T=T+B..显然T&amp;gt;B..如果当前 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23135.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23135.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Sat, 01 Sep 2012 01:19:02 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[把string转换为char* 的三种方法]]></title>
      <description><![CDATA[ 		一、data 
string str = &amp;quot;abc&amp;quot;;
char *p = const_cast&amp;lt;char*&amp;gt;(str.data());二、c_str
string str = &amp;quot;g ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23126.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23126.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 31 Aug 2012 06:59:00 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[如何向窗口发送消息]]></title>
      <description><![CDATA[ 		CWnd类的SendMessage和PostMessage成员函数.
第一步:在头文件中自定义消息,如:
cpp
#define WM_USER ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23125.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23125.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 31 Aug 2012 05:49:07 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ffmpeg+sdl+qt的一些问题]]></title>
      <description><![CDATA[ 		在做ffmpeg+Qt+SDL的项目的时候，出现这个错误，
/usr/local/lib/libavdevice.a(alsa-audio-dec.o): In  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23124.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23124.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 31 Aug 2012 03:37:06 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[一道迅雷笔试题引发的思考？—— 不重复随机算法]]></title>
      <description><![CDATA[ 		关于一种不重复随机算法，可以计算0 ~ n中不重复的m个数。cpp 
#include &amp;lt;iostream&amp;gt; 
#include &amp;lt;stdl ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23123.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23123.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 31 Aug 2012 03:10:58 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[Uva 10104 Euclid Problem |x|+|y|最小解 扩展欧几里得]]></title>
      <description><![CDATA[ 		cpp 
/*
*   url: http://uva.onlinejudge.org/index.php?option=com_onlinejudge&amp;amp;Itemid=8&amp;amp;page=sho ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23122.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23122.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 31 Aug 2012 03:06:28 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[POJ 3267 The Cow Lexicon]]></title>
      <description><![CDATA[ 		  这道题目看了我很久。     题意：给你一个主串，和一些单词，问你在主串中至少删除几个字母，是的剩下的 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23121.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23121.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 31 Aug 2012 02:52:39 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ UVA 11888 Abnormal 89&#039;s]]></title>
      <description><![CDATA[ 		Manacher的应用
cpp
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt;cstring&amp;gt; 
#include&amp;lt;cstdlib&amp;gt; 
#include&amp;lt;iostrea ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23120.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23120.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 31 Aug 2012 02:20:50 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ pthread 简要使用指南（二） joinable 与 detached]]></title>
      <description><![CDATA[ 		 pthread_craete()出来的线程，joinable或detached两者必占之一。    如果是jionale的线程，那么必须使用 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23119.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23119.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 31 Aug 2012 02:07:37 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[pthread 简要使用指南（一） pthread_create]]></title>
      <description><![CDATA[ 		POSIX thread 简称为pthread，Posix线程是一个POSIX标准线程。该标准定义内部API创建和操纵线程。 Pthrea ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23118.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23118.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 31 Aug 2012 02:04:10 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[调用STL的sort，出错提示invalid &amp;amp;lt;]]></title>
      <description><![CDATA[ 		  今天调用STL的sort函数，结果一直出错说 invalid &amp;lt; ，网上找了很久都没有找到相关解答，弄了许久终于弄 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23117.html</link>
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      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 31 Aug 2012 01:58:03 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[SGU 411 Petya the Hero]]></title>
      <description><![CDATA[ 		cpp 
求两个字符串最长公共回文字串，并随便输出一个 
 
#include&amp;lt;cstdio&amp;gt; 
#include&amp;lt;cstring&amp;gt; 
# ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23116.html</link>
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      <pubDate>Fri, 31 Aug 2012 01:41:00 +0000</pubDate>
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    <item>
      <title><![CDATA[HDU3779(Railroad)]]></title>
      <description><![CDATA[ 		java 
 
import java.util.*; 
 
public class Railroad { 
 
    static int arr1; 
    sta ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23115.html</link>
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      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 31 Aug 2012 01:36:45 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[排序（之插入排序）]]></title>
      <description><![CDATA[ 		插入排序是稳定的排序，平均情况和最坏情况的算法复杂度为O(n^2)，最好情况为O(n)；空间复杂度为：O(1)。 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23114.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23114.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Fri, 31 Aug 2012 01:04:03 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[为数据结构添加setProperty和getProperty]]></title>
      <description><![CDATA[ 		为手头游戏项目写编器，关联编器和游戏中的游戏对象的属性成了一个不小的问题，经过多经改写总算有一个相 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23113.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23113.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 30 Aug 2012 08:50:42 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[关于 Objective-C iVar 的一点说明]]></title>
      <description><![CDATA[ 		Class A:cpp 
@interface ClassA : NSObject{ 
} 
@property(nonatomic, retain) Foo* foo; 
@end  ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23112.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23112.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 30 Aug 2012 08:09:35 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[数据结构----二叉树的遍历]]></title>
      <description><![CDATA[ 		一．实验要求    二叉树的遍历操作是树形结构其他众多操作的基础。本实验旨在使学生进一步加深对二叉树的 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23211.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23211.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 30 Aug 2012 07:58:28 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ C++标准模板库复习]]></title>
      <description><![CDATA[ 		一、主要内容        泛型程序设计
与标准模板库有关的概念和术语
C++标准模板库中的容器
迭代器
标准 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23210.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23210.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 30 Aug 2012 06:57:37 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ uva 507 - Jill Rides Again]]></title>
      <description><![CDATA[ 		
题目意思：   有一个人想要骑自行车去旅游，但是现在有s-1条路，每一条都有一个值，正值表示他喜欢然后 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23209.html</link>
      <guid>http://www.syue.com/Software/Language/CPP/23209.html</guid>
      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 30 Aug 2012 06:33:24 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[ Uva 10168 Summation of Four Primes 素数]]></title>
      <description><![CDATA[ 		cpp 
/*
*   Status: 10540903    10168   Summation of Four Primes    Accepted    C++ 0.864   20 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23208.html</link>
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      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 30 Aug 2012 06:07:07 +0000</pubDate>
    </item>
    <item>
      <title><![CDATA[CodeForces Round #125 (198C) - Delivering Carcinogen]]></title>
      <description><![CDATA[ 		   题意抽象：       有点 p 在初始点 ( px , py ) 起逆时针等速度 p.v 沿着绿色大圆 R 转~~点 Q 在平面上 ]]></description>
      <link>http://www.syue.com/Software/Language/CPP/23207.html</link>
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      <category>C++</category>
      <author><![CDATA[]]></author>
      <pubDate>Thu, 30 Aug 2012 05:31:09 +0000</pubDate>
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